Question

# Evaluate the following trigonometric term$\sin {30^0}\cos {30^0}$

Given term: $\sin {30^0}\cos {30^0}$
$\sin {30^0} = \dfrac{1}{2} \\ \cos {30^0} = \dfrac{{\sqrt 3 }}{2} \\$
$\Rightarrow \sin {30^0}\cos {30^0} = \dfrac{1}{2} \times \dfrac{{\sqrt 3 }}{2} \\ = \dfrac{{\sqrt 3 }}{4} \\ = \dfrac{{1.732}}{4}\left[ {\because \sqrt 3 = 1.732} \right] \\ = 0.433 \\$
Hence, the value of $\sin {30^0}\cos {30^0}$ is $\dfrac{{\sqrt 3 }}{4}{\text{ or }}0.433$
Note- We know that sine of any angle in a right angled triangle is the ratio of the lengths of height upon the hypotenuse and cosine of any angle in a right angled triangle is the ratio of the lengths of base upon hypotenuse. The value of sine and cosine of some common angles like ${0^0},{30^0},{45^0},{60^0},{90^0},{180^0}$ are very important and they must be remembered.