
Energy of a photon having wave number $1.00c{m^{ - 1}}$ is
A. $6.62 \times {10^{ - 34}}J$
B. $1.99\times {10^{−23}} J$
C. $6.62\times {10^{−32}} J$
D. $6.62\times {10^{−36}} J$
Answer
578.1k+ views
Hint: To solve the above question, we need to know the relationship between the energy of a photon to its wavelength and frequency. By using this relation we can solve the energy of photons. Energy of a photon is the energy carried by each photon.
Complete step by step answer:
From the given data:
$\lambda = 1c{m^{ - 1}} = 0.01{m^{ - 1}}$
$
c = 3 \times {10^8}m{s^{ - 1}} \\
h = 6.625 \times {10^{ - 34}}Js \\
$
By using the energy of photon relation
$
E = h\nu \\
\Rightarrow E = \dfrac{{hc}}{\lambda } \\
$
Substituting the values for above equation,
$
E = \dfrac{{6.626 \times {{10}^{ - 34}} \times 3 \times {{10}^8}}}{{0.01}} \\
\Rightarrow E = \dfrac{{19.878 \times {{10}^{ - 26}}}}{{0.01}} \\
\Rightarrow E = 1987.8 \times {10^{ - 26}} \\
\Rightarrow E = 1.99 \times {10^{ - 23}}J \\
$
Hence the correct option is B.
Note:It’s very easy to solve this type of question by understanding the photoelectric equation and we should concentrate on the theory of photons. The energy of the photon is directly dependent on its frequency. If greater the energy of a photon then more the frequency. Usually a beam of light consists of many photons such as intensity red light which carry more energy and intensity of blue light which carry less energy.
Complete step by step answer:
From the given data:
$\lambda = 1c{m^{ - 1}} = 0.01{m^{ - 1}}$
$
c = 3 \times {10^8}m{s^{ - 1}} \\
h = 6.625 \times {10^{ - 34}}Js \\
$
By using the energy of photon relation
$
E = h\nu \\
\Rightarrow E = \dfrac{{hc}}{\lambda } \\
$
Substituting the values for above equation,
$
E = \dfrac{{6.626 \times {{10}^{ - 34}} \times 3 \times {{10}^8}}}{{0.01}} \\
\Rightarrow E = \dfrac{{19.878 \times {{10}^{ - 26}}}}{{0.01}} \\
\Rightarrow E = 1987.8 \times {10^{ - 26}} \\
\Rightarrow E = 1.99 \times {10^{ - 23}}J \\
$
Hence the correct option is B.
Note:It’s very easy to solve this type of question by understanding the photoelectric equation and we should concentrate on the theory of photons. The energy of the photon is directly dependent on its frequency. If greater the energy of a photon then more the frequency. Usually a beam of light consists of many photons such as intensity red light which carry more energy and intensity of blue light which carry less energy.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Why cannot DNA pass through cell membranes class 12 biology CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

