
How many electrons make up a charge of 20\[\mu C\]?
\[\begin{align}
& \text{A) 1}\text{.25}\times \text{1}{{\text{0}}^{14}} \\
& \text{B) 2}\text{.23}\times {{10}^{14}} \\
& \text{C) 3}\text{.25}\times {{10}^{14}} \\
& \text{D) 5}\text{.25}\times {{10}^{14}} \\
\end{align}\]
Answer
556.5k+ views
Hint: We need to understand the relation between the charge present in a system and the number of electrons that can constitute the given amount of charge. We can easily solve this problem using these relations to find the number of charges present.
Complete answer:
We know that the charges involved in a system especially in a conductor is either the presence of electrons or their absence such that positive ions are present. The magnitude of charge for both the cases will be the same, given by ‘e’ as \[1.6\times {{10}^{-19}}C\]. The positive ions can represent a positive charge whereas the negative ions or the electrons represent a negative charge.
The charge is a quantised quantity. The value of the charge present in a system can be only the multiples of the single charge ‘e’. There can never be a fractional value for the charge.
In the present case, we are given a charge of 20\[\mu C\]. We can find the number of electrons present or may be absent in this situation by simple mathematical calculation. We can apply the idea of the charge quantisation to solve this. We can divide the given charge by the charge of a single electron to get the number of electrons involved as –
\[\begin{align}
& \text{Number of electrons = }\dfrac{\text{Total charge}}{\text{Charge of one electron}} \\
& \Rightarrow n=\dfrac{20\times {{10}^{-6}}C}{1.6\times {{10}^{-19}}C} \\
& \therefore n=1.25\times {{10}^{14}}electrons \\
\end{align}\]
The number of electrons present in the system of total charge 20\[\mu C\] is \[\text{1}\text{.25}\times \text{1}{{\text{0}}^{14}}\].
From this information we get the verification that the charge is a quantised quantity which will be the whole number always.
The correct answer is option A.
Note:
The quantisation of electric charge is utilised in every aspect where the charges come into play. Even in chemistry, the balancing of chemical equations has the aim of making the electrons involved to be even on both sides so that it doesn’t violate quantisation.
Complete answer:
We know that the charges involved in a system especially in a conductor is either the presence of electrons or their absence such that positive ions are present. The magnitude of charge for both the cases will be the same, given by ‘e’ as \[1.6\times {{10}^{-19}}C\]. The positive ions can represent a positive charge whereas the negative ions or the electrons represent a negative charge.
The charge is a quantised quantity. The value of the charge present in a system can be only the multiples of the single charge ‘e’. There can never be a fractional value for the charge.
In the present case, we are given a charge of 20\[\mu C\]. We can find the number of electrons present or may be absent in this situation by simple mathematical calculation. We can apply the idea of the charge quantisation to solve this. We can divide the given charge by the charge of a single electron to get the number of electrons involved as –
\[\begin{align}
& \text{Number of electrons = }\dfrac{\text{Total charge}}{\text{Charge of one electron}} \\
& \Rightarrow n=\dfrac{20\times {{10}^{-6}}C}{1.6\times {{10}^{-19}}C} \\
& \therefore n=1.25\times {{10}^{14}}electrons \\
\end{align}\]
The number of electrons present in the system of total charge 20\[\mu C\] is \[\text{1}\text{.25}\times \text{1}{{\text{0}}^{14}}\].
From this information we get the verification that the charge is a quantised quantity which will be the whole number always.
The correct answer is option A.
Note:
The quantisation of electric charge is utilised in every aspect where the charges come into play. Even in chemistry, the balancing of chemical equations has the aim of making the electrons involved to be even on both sides so that it doesn’t violate quantisation.
Recently Updated Pages
A man running at a speed 5 ms is viewed in the side class 12 physics CBSE

The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

State and explain Hardy Weinbergs Principle class 12 biology CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Which of the following statements is wrong a Amnion class 12 biology CBSE

Differentiate between action potential and resting class 12 biology CBSE

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

How much time does it take to bleed after eating p class 12 biology CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

Explain sex determination in humans with the help of class 12 biology CBSE

