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How many electrons are present in a particle which carries a charge of $5.5 \times {10^{ - 16}}C$?A. 3432B. 1560C. 8240D. 2432

Last updated date: 20th Jun 2024
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Hint: The electron is a subatomic particle present in an atom along with other subatomic particles such as protons and neutrons. The total number of electrons and protons in an atom determines the net charge of an atom. The elementary charge of an electron has an approximate value of $1.6022 \times {10^{ - 19}}C$. The elementary charge here refers to the electric charge carried by a single electron. It is denoted as –e for an electron.

Formula used: The formula we will be using to calculate the number of electrons present in the particle is:
$n = \dfrac{q}{e}$
The letter ‘n’ denotes the number of electrons present in the particle carrying charge of the magnitude of $5.5 \times {10^{ - 16}}C$. The C here is the charge of the particle of which number of electrons we have to find and e is the elementary charge of an electron.

Complete step by step answer:
The charge is also referred to as the electric charge, electrical charge or electrostatic charge. It is denoted by the symbol q. The charge is expressed as the extent to which a particle has more or less electrons than protons with positive charge. The SI unit of charge is coulomb or C. Charge is said to be quantized, that is charge is expressed in the multiple of charge on an electron or a proton.
As we know, the charge is quantized and this can be expressed as:
$q = n \times e$………… (1)
As we know, q is the symbol used for expressing charge in coulombs, n is the number of electrons present in the particle and it can be positive or negative value. The elementary charge equals to $1.6022 \times {10^{ - 19}}C$.
To obtain the number of electrons present in particle we need to rearrange formula (1)
On rearranging the formula (1), we get,
$n = \dfrac{q}{e}$……………….. (2)
We will now substitute the respective values in formula (2) to find out the number of electrons in the said particle.
Let us first write down the given values.
$q = 5.5 \times {10^{ - 16}}C$
$e = 1.6022 \times {10^{ - 19}}C$
On putting respective values in formula (2), we get,
$n = \dfrac{{5.5 \times {{10}^{ - 19}}C}}{{1.6022 \times {{10}^{ - 16}}C}}$
$\therefore n = 3432electrons$
The number of electrons present in a particle carrying charge of $5.5 \times {10^{ - 16}}C$ is 3432.

So, the correct answer is A.