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How can I draw the Lewis structure for ${{H}_{2}}O$ ?

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Last updated date: 20th Jun 2024
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Answer
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Hint Lewis dot structures also known as electron dot structures. Lewis dot structures represent the valence electrons of the atoms present within the given molecule. By Lewis dot structures we can visualize the bonding electrons and lone pair of electrons present in the molecule.

Complete answer:
- In the question it is given that to draw the Lewis dot structures of the water molecule.
- We know that the atomic number of oxygen is 8 and has eight electrons in its electronic configuration.
- The electronic configuration of oxygen is $1{{s}^{2}}2{{s}^{2}}2{{p}^{4}}$
- So oxygen has six valence electrons in 2s and 2p orbital.
- The Lewis dot structure of the beryllium is as follows.
- Coming to hydrogen, we know that the hydrogen element has one valence electron in its electronic configuration.
- The Lewis dot structure of hydrogen is as follows.
- Now by taking the above structures as examples we can draw the Lewis dot structure of ${{H}_{2}}O$ and it is as follows.
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- From the above Lewis dot structure we can easily say that an oxygen atom has two lone pairs of electrons and hydrogen has zero lone pair of electrons in water molecules.

Note: By using Lewis dot structures of the molecules we can determine the formation of the chemical bonds in various molecules. We can draw the Lewis dot structures for the compounds containing covalent bonds and also we can draw for coordination compounds.