Courses
Courses for Kids
Free study material
Free LIVE classes
More
LIVE
Join Vedantu’s FREE Mastercalss

Draw a line segment AB of length 10 cm. Mark a point P on AB such that AP = 4 cm. Draw a line through P perpendicular to AB.

Answer
VerifiedVerified
363k+ views
Hint: First of all, draw a line AB = 10 cm and mark point P such that AP = 4 cm. Now mark two points on both sides of P on line AB equidistant from P. Now with the centers at these points, draw an arc above line AB and proceed to get the required perpendicular.

Complete step-by-step answer:
Here, we have to draw a line segment AB of length 10 cm. Then, we have to mark a point P on AB such that AP = 4 cm. Finally, we have to draw a line through P which would be perpendicular to AB.
(i) Let us first draw the line AB = 10 cm with the help of a ruler as follows:
seo images

(ii) Now, with A as the center and 4 cm as the radius, we will draw an arc on AB as
seo images

(iii) We will name this point as P such that AP = 4 cm.
seo images

(iv) Now, we will take any radius, say 3 cm. With P as center and radius = 3 cm. We will draw an arc on the left side of P on line AB as,
seo images

(v) We will name this as point C.
seo images

(vi) Now with the same radius that is 3 cm and with P as the center, we will again draw an arc on the right side of P on the line AB as,
seo images

(vii) We will name this as point D.
seo images

(viii) Now with D as center and radius greater than DP, we will draw an arc above line AB as,
seo images

(ix) Now with C as the center and with the same radius as that of the previous step, we will draw an arc cutting the previous arc and we will name this point of intersection of two arcs as O.
seo images

(x) Now we will join OP and extend it.
seo images

Hence, we get OP as the required perpendicular on line AB through P.

Note: Some students make this mistake of constructing the perpendicular bisector of AB but they must keep in mind that they have to construct perpendicular passing through P. Also, students can cross-check their construction by measuring if angle \[\angle OPD\] is \[{{90}^{o}}\] or not.
Last updated date: 02nd Oct 2023
Total views: 363k
Views today: 8.63k
Trending doubts