Answer
Verified
469.8k+ views
Hint: Here, the given problem can be solved by simplifying the given function first
and then applying the suitable formulae of differentiation.
Given,
${x^{ - 4}}(3 - 4{x^{ - 5}}) \to (1)$
Let us simply the equation (1), we get
$3{x^{ - 4}} - 4{x^{ - 9}} \to (2)$
Now, we need to find the differentiation of equation (2) with respect to x i.e..,
$\begin{gathered}
\Rightarrow \frac{d}{{dx}}(3{x^{ - 4}} - 4{x^{ - 9}}) \\
\Rightarrow \frac{d}{{dx}}(3{x^{ - 4}}) - \frac{d}{{dx}}(4{x^{ - 9}}) \\
\Rightarrow 3\frac{d}{{dx}}({x^{ - 4}}) - 4\frac{d}{{dx}}({x^{ - 9}}) \\
\end{gathered} $
As we know that$\frac{d}{{dx}}({x^n}) = n.{x^{n - 1}}$.So applying the formulae, we get
$\begin{gathered}
\Rightarrow (3( - 4){x^{ - 4 - 1}}) - (4( - 9){x^{ - 9 - 1}}) \\
\Rightarrow - 12{x^{ - 5}} + 36{x^{ - 10}} \\
\end{gathered} $
Therefore$\frac{d}{{dx}}({x^{ - 4}}(3 - 4{x^{ - 5}})) = - 12{x^{ - 5}} + 36{x^{ - 10}}$.
Note: The differentiation formula of ${x^n}$i.e.., $\frac{d}{{dx}}({x^n}) = n.{x^{n - 1}}$can be
used for any value of n i.e.., it will be applicable even the value of n is positive, negative or
fractional value.
and then applying the suitable formulae of differentiation.
Given,
${x^{ - 4}}(3 - 4{x^{ - 5}}) \to (1)$
Let us simply the equation (1), we get
$3{x^{ - 4}} - 4{x^{ - 9}} \to (2)$
Now, we need to find the differentiation of equation (2) with respect to x i.e..,
$\begin{gathered}
\Rightarrow \frac{d}{{dx}}(3{x^{ - 4}} - 4{x^{ - 9}}) \\
\Rightarrow \frac{d}{{dx}}(3{x^{ - 4}}) - \frac{d}{{dx}}(4{x^{ - 9}}) \\
\Rightarrow 3\frac{d}{{dx}}({x^{ - 4}}) - 4\frac{d}{{dx}}({x^{ - 9}}) \\
\end{gathered} $
As we know that$\frac{d}{{dx}}({x^n}) = n.{x^{n - 1}}$.So applying the formulae, we get
$\begin{gathered}
\Rightarrow (3( - 4){x^{ - 4 - 1}}) - (4( - 9){x^{ - 9 - 1}}) \\
\Rightarrow - 12{x^{ - 5}} + 36{x^{ - 10}} \\
\end{gathered} $
Therefore$\frac{d}{{dx}}({x^{ - 4}}(3 - 4{x^{ - 5}})) = - 12{x^{ - 5}} + 36{x^{ - 10}}$.
Note: The differentiation formula of ${x^n}$i.e.., $\frac{d}{{dx}}({x^n}) = n.{x^{n - 1}}$can be
used for any value of n i.e.., it will be applicable even the value of n is positive, negative or
fractional value.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Mark and label the given geoinformation on the outline class 11 social science CBSE
When people say No pun intended what does that mea class 8 english CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Give an account of the Northern Plains of India class 9 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Trending doubts
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Difference Between Plant Cell and Animal Cell
Which are the Top 10 Largest Countries of the World?
Write a letter to the principal requesting him to grant class 10 english CBSE
10 examples of evaporation in daily life with explanations
Give 10 examples for herbs , shrubs , climbers , creepers
Change the following sentences into negative and interrogative class 10 english CBSE