
Differentiate the following function with respect to x
${x^{ - 4}}(3 - 4{x^{ - 5}})$
Answer
632.7k+ views
Hint: Here, the given problem can be solved by simplifying the given function first
and then applying the suitable formulae of differentiation.
Given,
${x^{ - 4}}(3 - 4{x^{ - 5}}) \to (1)$
Let us simply the equation (1), we get
$3{x^{ - 4}} - 4{x^{ - 9}} \to (2)$
Now, we need to find the differentiation of equation (2) with respect to x i.e..,
$\begin{gathered}
\Rightarrow \frac{d}{{dx}}(3{x^{ - 4}} - 4{x^{ - 9}}) \\
\Rightarrow \frac{d}{{dx}}(3{x^{ - 4}}) - \frac{d}{{dx}}(4{x^{ - 9}}) \\
\Rightarrow 3\frac{d}{{dx}}({x^{ - 4}}) - 4\frac{d}{{dx}}({x^{ - 9}}) \\
\end{gathered} $
As we know that$\frac{d}{{dx}}({x^n}) = n.{x^{n - 1}}$.So applying the formulae, we get
$\begin{gathered}
\Rightarrow (3( - 4){x^{ - 4 - 1}}) - (4( - 9){x^{ - 9 - 1}}) \\
\Rightarrow - 12{x^{ - 5}} + 36{x^{ - 10}} \\
\end{gathered} $
Therefore$\frac{d}{{dx}}({x^{ - 4}}(3 - 4{x^{ - 5}})) = - 12{x^{ - 5}} + 36{x^{ - 10}}$.
Note: The differentiation formula of ${x^n}$i.e.., $\frac{d}{{dx}}({x^n}) = n.{x^{n - 1}}$can be
used for any value of n i.e.., it will be applicable even the value of n is positive, negative or
fractional value.
and then applying the suitable formulae of differentiation.
Given,
${x^{ - 4}}(3 - 4{x^{ - 5}}) \to (1)$
Let us simply the equation (1), we get
$3{x^{ - 4}} - 4{x^{ - 9}} \to (2)$
Now, we need to find the differentiation of equation (2) with respect to x i.e..,
$\begin{gathered}
\Rightarrow \frac{d}{{dx}}(3{x^{ - 4}} - 4{x^{ - 9}}) \\
\Rightarrow \frac{d}{{dx}}(3{x^{ - 4}}) - \frac{d}{{dx}}(4{x^{ - 9}}) \\
\Rightarrow 3\frac{d}{{dx}}({x^{ - 4}}) - 4\frac{d}{{dx}}({x^{ - 9}}) \\
\end{gathered} $
As we know that$\frac{d}{{dx}}({x^n}) = n.{x^{n - 1}}$.So applying the formulae, we get
$\begin{gathered}
\Rightarrow (3( - 4){x^{ - 4 - 1}}) - (4( - 9){x^{ - 9 - 1}}) \\
\Rightarrow - 12{x^{ - 5}} + 36{x^{ - 10}} \\
\end{gathered} $
Therefore$\frac{d}{{dx}}({x^{ - 4}}(3 - 4{x^{ - 5}})) = - 12{x^{ - 5}} + 36{x^{ - 10}}$.
Note: The differentiation formula of ${x^n}$i.e.., $\frac{d}{{dx}}({x^n}) = n.{x^{n - 1}}$can be
used for any value of n i.e.., it will be applicable even the value of n is positive, negative or
fractional value.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
Draw a diagram of nephron and explain its structur class 11 biology CBSE

Explain zero factorial class 11 maths CBSE

Chemical formula of Bleaching powder is A Ca2OCl2 B class 11 chemistry CBSE

Name the part of the brain responsible for the precision class 11 biology CBSE

The growth of tendril in pea plants is due to AEffect class 11 biology CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

