Answer

Verified

392.7k+ views

**Hint:**As we know that due to collision of molecules the speeds and kinetic energies of individual molecules keeps on changing and to calculate these speeds like RMS i.e the root mean square velocity as the name implies we first take square of the individual speeds and then their mean.

**Complete Step by step answer:**

> As we know that due to collision of molecules the speeds and kinetic energies of individual molecules keeps on changing. However, at a given temperature the average kinetic energy of a gas molecule remains constant.

> Let us assume that at a given temperature we have to calculate these speeds like RMS i.e the root mean square velocity as the name implies we first take the square of the individual speeds which may be assumed as ${V_1},{V_2}..$and ${n_1},{n_2}..$be the number of molecules then we will take mean and finally the square root of mean. Mathematically it can be represented as:

${V_{rms}} = \sqrt {\dfrac{{3RT}}{M}} $where R is the gas constant, T is the temperature and M is the molecular mass of the gas.

Using this formula we can identify the RMS velocity of the gas. But in the question we are given with density and pressure of the gas and no information regarding which gas so to calculate the RMS speed we need to change the above formula in terms of pressure and density.

As we know that, $PV = nRT$ and $density = \dfrac{{mass}}{{volume}}$ using these two,

$

PV = nRT \\

\Rightarrow PM = dRT \\

\Rightarrow M = \dfrac{{dRT}}{P} \\

$

Putting the value of M in the RMS speed formula we get,

$

{V_{rms}} = \sqrt {\dfrac{{3RTP}}{{dRT}}} \\

\Rightarrow {V_{rms}} = \sqrt {\dfrac{{3P}}{d}} \\

$

Now, we know $d = 1.43 \times {10^{ - 2}}g\;c{c^{ - 1}}$and , to calculate the speed in $m{s^{ - 1}}$we will change $d = 1.43\;Kg{m^{ - 3}}$$P = 1atm = 1.013 \times {10^5}N{m^{ - 2}}$thus putting these values in the formula:

$

{V_{rms}} = \sqrt {\dfrac{{3P}}{d}} \\

\Rightarrow {V_{rms}} = \sqrt {\dfrac{{3 \times 1.013 \times {{10}^5}}}{{1.43}}} \\

\Rightarrow {V_{rms}} = 461m{s^{ - 1}} \\

$

**Therefore, the correct answer is, ${V_{rms}} = 461m{s^{ - 1}}$.**

**Note:**Remember that the RMS speed is directly proportional to the square root of the temperature and inversely proportional to the square root of mass, thus when the temperature is increased its RMS speed will increase.

Recently Updated Pages

Which of the following is the correct formula of Gypsum class 10 chemistry CBSE

Biogas is a mixture of A Methane + CO 2 B Methane + class 10 chemistry CBSE

Graphite is a good conductor of electricity due to class 10 chemistry CBSE

What is the number of valence electrons in the Clion class 10 chemistry CBSE

Which oxidation state for nitrogen is correctly given class 10 chemistry CBSE

Why do we store silver chloride in dark colored bo class 10 chemistry CBSE

Trending doubts

Difference Between Plant Cell and Animal Cell

Give 10 examples for herbs , shrubs , climbers , creepers

Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE

Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

Name 10 Living and Non living things class 9 biology CBSE

Change the following sentences into negative and interrogative class 10 english CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

Select the word that is correctly spelled a Twelveth class 10 english CBSE

Fill the blanks with proper collective nouns 1 A of class 10 english CBSE