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# What is the decreasing order of boiling points of the ${\rm{V}}$ group of hydrides?A.$N{H_3} > P{H_3} > As{H_3} > Sb{H_3}$B.$Sb{H_3} > As{H_3} > P{H_3} > N{H_3}$C.$P{H_3} > N{H_3} > As{H_3} > Sb{H_3}$D.$Sb{H_3} > N{H_3} > As{H_3} > P{H_3}$

Last updated date: 26th Mar 2023
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Hint: Group ${\rm{V}}$ in the periodic table is known as the nitrogen family and main elements of this group are nitrogen, phosphorus, arsenic, antimony and bismuth. As there are three electrons present in the valence subshell of each element therefore the elements of the nitrogen family form hydrides of types $A{H_3}$.

As we know, on moving down the group the atomic size of the elements increases therefore the Vander Waal forces acting between the atoms also increases which leads to increase in the bond strength of molecules. As the bond strength of a molecule increases, the molecule will require more heat to break its bonds. Therefore, the boiling points of hydrides ${\rm{V}}$ group increases down the group.
Therefore, the correct decreasing order of boiling points of ${\rm{V}}$ group of hydrides is $Sb{H_3} > N{H_3} > As{H_3} > P{H_3}$