
Cory has \[6\] times as many as mike. Phil has half as many as Judy. Judy has half as many as Cory. Mike has $6$ cookies. How many cookies does Phil have ?
Answer
495.3k+ views
Hint: Multiplication is when you take one number and add it together a number of times. First we collect the given data and using multiplication we find how many cookies Mike has. After that we find one by one how many cookies Cory and Judy have. After that we find our required answer.
Complete step-by-step answer:
Given that Mike has $6$ cookies.
Now we have a condition that Cory has $6$ times as many as Mike
Therefore Cory have = $6 \times 6$
$ = 36$ cookies.
Now we find how many cookies have Judy
We have a condition that Judy has half as many as Cory
Therefore Cory have $ = \dfrac{1}{2} \times 36$
$ = 18$ cookies.
Now we find how many cookies have Phil
We have a condition Phil has half as many as Judy
Therefore Phil have $ = \dfrac{1}{2} \times 18$
$ = 9$ cookies.
The required answer is that Phil has $9$ cookies.
So, the correct answer is “9”.
Note: Students have to remember that the sentence “Someone has half as many as another-one” means Someone has equal to half of another-one have and students take care in the multiplication and division steps. We solve the given problem in another method which is one step method :
The step $ = $ $\dfrac{1}{4} \times $ Cory have
Where Cory have $ = 6$ times of Mike [Mike have $6$ cookies]
$ = 6 \times 6$
Now we find how many cookies Phil have
Therefore, Phil have
$ = \dfrac{1}{4} \times 6 \times 6$
$ = 3 \times 3$
$ = 9$ cookies.
The required answer is $9$ cookies.
Complete step-by-step answer:
Given that Mike has $6$ cookies.
Now we have a condition that Cory has $6$ times as many as Mike
Therefore Cory have = $6 \times 6$
$ = 36$ cookies.
Now we find how many cookies have Judy
We have a condition that Judy has half as many as Cory
Therefore Cory have $ = \dfrac{1}{2} \times 36$
$ = 18$ cookies.
Now we find how many cookies have Phil
We have a condition Phil has half as many as Judy
Therefore Phil have $ = \dfrac{1}{2} \times 18$
$ = 9$ cookies.
The required answer is that Phil has $9$ cookies.
So, the correct answer is “9”.
Note: Students have to remember that the sentence “Someone has half as many as another-one” means Someone has equal to half of another-one have and students take care in the multiplication and division steps. We solve the given problem in another method which is one step method :
The step $ = $ $\dfrac{1}{4} \times $ Cory have
Where Cory have $ = 6$ times of Mike [Mike have $6$ cookies]
$ = 6 \times 6$
Now we find how many cookies Phil have
Therefore, Phil have
$ = \dfrac{1}{4} \times 6 \times 6$
$ = 3 \times 3$
$ = 9$ cookies.
The required answer is $9$ cookies.
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