
What is the correct relationship?
(A) ${{E}_{1}}ofH=1/2{{E}_{2}}ofH{{e}^{+}}=1/3{{E}_{3}}ofL{{i}^{2+}}=1/4{{E}_{4}}ofB{{e}^{3+}}$
(B) ${{E}_{1}}(H)={{E}_{2}}(H{{e}^{+}})={{E}_{3}}(L{{i}^{2+}})={{E}_{4}}(B{{e}^{3+}})$
(C) ${{E}_{1}}(H)=2{{E}_{2}}(H{{e}^{+}})=3{{E}_{3}}(L{{i}^{2+}})=4{{E}_{4}}(B{{e}^{3+}})$
(D) No relation
Answer
512.7k+ views
Hint: Hydrogen atom is the simplest atom to apply Bohr model and Schrodinger equation. An atom in its normal state has Z protons and Z electrons in order to be neutral. Z is called the atomic number. From the Bohr’s equation, can calculate the energy of electron like single atoms H, $H{{e}^{+2}},L{{i}^{+3}} and,B{{e}^{+4}}$ .
Complete answer:
In the equation given, ${{E}_{n}}$ = energy of nth orbit
We know, hydrogen like single atom, energy of the nth orbit, \[{{E}_{n}}=-13.6X\dfrac{{{Z}^{2}}}{{{n}^{2}}}eV\] -- (1)
Where, Z = atomic number of atoms, and n= number of orbits. This equation is known as energy of electrons in the Bohr orbit of the H atom.
Now, for H atom, the first energy level, ${{E}_{1}}$ will be, (from equation-1)
\[{{E}_{1}}=-13.6\dfrac{{{(1)}^{2}}}{{{(1)}^{2}}}=-13.6eV\]--- (2), where Z= atomic number of H =1 and energy level n =1
For $H{{e}^{+2}}$ atom, ${{E}_{2}}$ will be (from equation-1),
\[{{E}_{2}}=-13.6\dfrac{{{(2)}^{2}}}{{{(2)}^{2}}}=-13.6eV\]--- (3), where Z= 2 for He and n=2
For $L{{i}^{+3}}$ , ${{E}_{3}}$ will be (from equation-1),
\[{{E}_{3}}=-13.6\dfrac{{{(3)}^{2}}}{{{(3)}^{2}}}=-13.6eV\] -- (4), where Z=3 for Li and n=3
For $B{{e}^{+4}}$ , ${{E}_{4}}$ will be (from equation-1),
\[{{E}_{4}}=-13.6\dfrac{{{(4)}^{2}}}{{{(4)}^{2}}}=-13.6eV\] -- (5), where Z=4 for Be and n=3
From equation (2), (3), (4) and (5), the energy of electrons for a single electron atom is of equal value.
Hence, ${{E}_{1}}(H)={{E}_{2}}(H{{e}^{+}})={{E}_{3}}(L{{i}^{2+}})={{E}_{4}}(B{{e}^{3+}})$
So the correct answer is option B
Note:
An electron in an orbit is to ignore the interactions between electrons with each other and assume each electron is moving under the action of the nucleus as a point charge +Ze. Each electron has an independent potential energy and wave function.
Complete answer:
In the equation given, ${{E}_{n}}$ = energy of nth orbit
We know, hydrogen like single atom, energy of the nth orbit, \[{{E}_{n}}=-13.6X\dfrac{{{Z}^{2}}}{{{n}^{2}}}eV\] -- (1)
Where, Z = atomic number of atoms, and n= number of orbits. This equation is known as energy of electrons in the Bohr orbit of the H atom.
Now, for H atom, the first energy level, ${{E}_{1}}$ will be, (from equation-1)
\[{{E}_{1}}=-13.6\dfrac{{{(1)}^{2}}}{{{(1)}^{2}}}=-13.6eV\]--- (2), where Z= atomic number of H =1 and energy level n =1
For $H{{e}^{+2}}$ atom, ${{E}_{2}}$ will be (from equation-1),
\[{{E}_{2}}=-13.6\dfrac{{{(2)}^{2}}}{{{(2)}^{2}}}=-13.6eV\]--- (3), where Z= 2 for He and n=2
For $L{{i}^{+3}}$ , ${{E}_{3}}$ will be (from equation-1),
\[{{E}_{3}}=-13.6\dfrac{{{(3)}^{2}}}{{{(3)}^{2}}}=-13.6eV\] -- (4), where Z=3 for Li and n=3
For $B{{e}^{+4}}$ , ${{E}_{4}}$ will be (from equation-1),
\[{{E}_{4}}=-13.6\dfrac{{{(4)}^{2}}}{{{(4)}^{2}}}=-13.6eV\] -- (5), where Z=4 for Be and n=3
From equation (2), (3), (4) and (5), the energy of electrons for a single electron atom is of equal value.
Hence, ${{E}_{1}}(H)={{E}_{2}}(H{{e}^{+}})={{E}_{3}}(L{{i}^{2+}})={{E}_{4}}(B{{e}^{3+}})$
So the correct answer is option B
Note:
An electron in an orbit is to ignore the interactions between electrons with each other and assume each electron is moving under the action of the nucleus as a point charge +Ze. Each electron has an independent potential energy and wave function.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
Which one of the following is a true fish A Jellyfish class 12 biology CBSE

Which are the Top 10 Largest Countries of the World?

Why is insulin not administered orally to a diabetic class 12 biology CBSE

a Tabulate the differences in the characteristics of class 12 chemistry CBSE

Why is the cell called the structural and functional class 12 biology CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
