Question

Convert ${{20}^{\circ}}$C into Kelvin and Fahrenheit scale.

Answer 1

Hint: The three main temperature scales are Celsius, Fahrenheit, and Kelvin. Temperature conversion equations are used to convert temperatures from one scale to another. The three phases of water (ice, liquid water, and water vapor) can coexist at a single pressure and temperature known as the triple point.

Complete step by step answer:
To convert one temperature unit to another, no complicated math is required. Conversions between the Kelvin and Celsius temperature scales are as simple as addition and subtraction. Fahrenheit requires some multiplication, but nothing too difficult. Simply enter the known value into the appropriate conversion formula to obtain the answer in the desired temperature scale.
Kelvin to Celsius: \[C\text{ }=\text{ }K\text{ }-\text{ }273\text{ }\left( C\text{ }=\text{ }K\text{ }-\text{ }273.15\text{ }if\text{ }you\text{ }want\text{ }to\text{ }be\text{ }more\text{ }precise \right)\]
Kelvin to Fahrenheit: \[F\text{ }=\text{ }\dfrac{9}{5}\left( K\text{ }-\text{ }273 \right)\text{ }+\text{ }32\text{ }or\text{ }F\text{ }=\text{ }1.8\left( K\text{ }-\text{ }273 \right)\text{ }+\text{ }32\]
Celsius to Fahrenheit: \[F\text{ }=\text{ }\dfrac{9}{5}\left( C \right)\text{ }+\text{ }32\text{ }or\text{ }F\text{ }=\text{ }1.80\left( C \right)\text{ }+\text{ }32\]
Celsius to Kelvin: \[K\text{ }=\text{ }C\text{ }+\text{ }273\text{ }\left( or\text{ }K\text{ }=\text{ }C\text{ }+\text{ }271.15\text{ }to\text{ }be\text{ }more\text{ }precise \right)\]
Fahrenheit to Celsius: \[C\text{ }=\text{ }\dfrac{\left( F\text{ }-\text{ }32 \right)}{1.80}\]
Fahrenheit to Kelvin: \[K\text{ }=\text{ }\dfrac{5}{9}\left( F\text{ }-\text{ }32 \right)\text{ }+\text{ }273.15\]
Remember to report Celsius and Fahrenheit values in degrees. There is no degree using the Kelvin scale.
So, by using, Celsius to Fahrenheit: \[F\text{ }=\text{ }\dfrac{9}{5}\left( C \right)\text{ }+\text{ }32\text{ }or\text{ }F\text{ }=\text{ }1.80\left( C \right)\text{ }+\text{ }32\] formula,
\[\begin{align}
  & {{T}_{({}^\circ F)}}=T({}^\circ C)\times \dfrac{9}{5}+32 \\
 & \Rightarrow {{T}_{({}^\circ F)}}=20{}^\circ C\times \dfrac{9}{5}+32=68{}^\circ F \\
\end{align}\]
Also, to convert celsius to Kelvin use,
 Celsius to Kelvin: \[K\text{ }=\text{ }C\text{ }+\text{ }273\text{ }\left( or\text{ }K\text{ }=\text{ }C\text{ }+\text{ }271.15\text{ }to\text{ }be\text{ }more\text{ }precise \right)\]formula,
\[\begin{align}
  & {{T}_{(K)}}={{T}_{({}^\circ C)}}+273.15 \\
 & \Rightarrow {{T}_{(K)}}=20+273.15=293.15K \\
\end{align}\]
Thus, ${{20}^{\circ}}$C is equal to \[{{68}^{\circ}}F\] and \[293.15K\].

Note: The most commonly used methods are Kelvin, Celsius, and Fahrenheit. Water has a freezing point of 273.15K and a boiling point of 373.15K on the Kelvin scale. Water has a freezing point of $32^{\circ}$F and a boiling point of $212^{\circ}$F on the Fahrenheit scale. Water has a freezing point of $0^{\circ}$C and a boiling point of $100^{\circ}$C on the Celsius scale.