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**Hint:**In this question, we are given a decimal number and there is a repetition of 94 in the given number. The decimal can be written as $0.\overline {94} $ , where the repetition is denoted by the bar on the digits 94, so the given number is irrational. Now the number $0.\overline {94} $can be converted to a fraction by multiplying the given number with a power of 10 such that the power is equal to the number of digits that are repeated and again multiply the obtained number with the same power of 10. By subtracting the obtained equations we can reach the correct answer.

**Complete step by step solution:**

The given number is $0.\overline {94} $ , it can be rewritten as $0.949494.....$ , let $0.\overline {94} = R$

In the given question, the number of repeating digits is 2 (94). So we first multiply $0.\overline {94} $ with ${10^2}$ and then the obtained number with ${10^2}$ , then we subtract both the results with each other, as follows –

$

{10^2} \times R = {10^2} \times 0.949494.... \\

\Rightarrow 100R = 94.9494...\,\,\,\,\,\,\,\,\,...(1) \\

{10^2} \times (1) = {10^2} \times 94.9494... \\

\Rightarrow 10000R = 9494.9494.....\,\,\,\,\,\,...(2) \\

(2) - (1) \\

10000R - 100R = 9494.9494..... - 94.9494.... \\

\Rightarrow 9900R = 9400 \\

\Rightarrow R = \dfrac{{9400}}{{9900}} \\

\Rightarrow R = \dfrac{{94}}{{99}} \\

$

Hence, the recurring decimal $0.\overline {94} $ is written in the fraction form as $\dfrac{{94}}{{99}}$

**Note:**Real numbers are of two types namely, Rational numbers and Irrational numbers. The numbers whose decimal expansion is terminating and non-repeating are called rational numbers and thus they can be expressed as a fraction such that the denominator is not zero, whereas irrational numbers are those which have repeating and non-terminating decimal expansion, the number $0.\overline {94} $ is irrational. So, we can convert the irrational numbers into a fraction using the method shown above.

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