
Consider three sets A, B, C such that A = {2, 3}, B = {4, 5} and C = {5, 6}. Find,
(i) $A\times \left( B\cap C \right)$
(ii) $\left( A\times B \right)\cup \left( B\times C \right)$
Answer
628.8k+ views
Hint: For any two sets A and B, the intersection of the two sets A and B (denoted by $A\cap B$) can be found by forming a set which contains the common elements of set A and set B. The cross product of two sets A and B (denoted by $A\times B$) is given by pairing each element of set A with each element of set B. Also, the union of the two sets A and B (denoted by $A\cup B$) is the set of elements which are in set A, in set B, or in both set A and set B. Using this, we can solve this question.
Complete step by step solution:
In the question, we are given three sets A, B, C such that A = {2, 3}, B = {4, 5} and C = {5, 6}.
(i) In this part, we are required to find $A\times \left( B\cap C \right)$.
The intersection of the two sets B and C (denoted by \[B\cap C\]) can be found by forming a set which contains the common elements of set B and set C. So, we can say,
\[B\cap C\] = {5}
The cross product of two sets A and \[B\cap C\] (denoted by $A\times \left( B\cap C \right)$) is given by pairing each element of set A with each element of set \[B\cap C\].
$\begin{align}
& \Rightarrow A\times \left( B\cap C \right)=\{2,3\}\times \{5\} \\
& \Rightarrow A\times \left( B\cap C \right)=\{\left( 2,5 \right),\left( 3,5 \right)\} \\
\end{align}$
(ii) In this part, we are required to find $\left( A\times B \right)\cup \left( B\times C \right)$.
The cross product of two sets A and B (denoted by $A\times B$) is given by pairing each element of set A with each element of set B.
$\Rightarrow A\times B=\{\left( 2,4 \right),\left( 2,5 \right),\left( 3,4 \right),\left( 3,5 \right)\}$
Similarly, we can find $B\times C=\left\{ \left( 4,5 \right),\left( 4,6 \right),\left( 5,5 \right),\left( 5,6 \right) \right\}$.
We have to find the union of the above to obtain cross products which are given by forming a set of elements in set $A\times B$, or in set $B\times C$, or in both the sets.
So, $\left( A\times B \right)\cup \left( B\times C \right)=\left\{ \left( 2,4 \right),\left( 2,5 \right),\left( 3,4 \right),\left( 3,5 \right),\left( 4,5 \right),\left( 4,6 \right),\left( 5,5 \right),\left( 5,6 \right) \right\}$.
Note: It is an easy question which can be done by the basic knowledge of set theory. The only possibility of error in this question is that if one misreads the question. There is a possibility that one may read the union sign as intersection sign or vice versa which may lead us to an incorrect answer.
Complete step by step solution:
In the question, we are given three sets A, B, C such that A = {2, 3}, B = {4, 5} and C = {5, 6}.
(i) In this part, we are required to find $A\times \left( B\cap C \right)$.
The intersection of the two sets B and C (denoted by \[B\cap C\]) can be found by forming a set which contains the common elements of set B and set C. So, we can say,
\[B\cap C\] = {5}
The cross product of two sets A and \[B\cap C\] (denoted by $A\times \left( B\cap C \right)$) is given by pairing each element of set A with each element of set \[B\cap C\].
$\begin{align}
& \Rightarrow A\times \left( B\cap C \right)=\{2,3\}\times \{5\} \\
& \Rightarrow A\times \left( B\cap C \right)=\{\left( 2,5 \right),\left( 3,5 \right)\} \\
\end{align}$
(ii) In this part, we are required to find $\left( A\times B \right)\cup \left( B\times C \right)$.
The cross product of two sets A and B (denoted by $A\times B$) is given by pairing each element of set A with each element of set B.
$\Rightarrow A\times B=\{\left( 2,4 \right),\left( 2,5 \right),\left( 3,4 \right),\left( 3,5 \right)\}$
Similarly, we can find $B\times C=\left\{ \left( 4,5 \right),\left( 4,6 \right),\left( 5,5 \right),\left( 5,6 \right) \right\}$.
We have to find the union of the above to obtain cross products which are given by forming a set of elements in set $A\times B$, or in set $B\times C$, or in both the sets.
So, $\left( A\times B \right)\cup \left( B\times C \right)=\left\{ \left( 2,4 \right),\left( 2,5 \right),\left( 3,4 \right),\left( 3,5 \right),\left( 4,5 \right),\left( 4,6 \right),\left( 5,5 \right),\left( 5,6 \right) \right\}$.
Note: It is an easy question which can be done by the basic knowledge of set theory. The only possibility of error in this question is that if one misreads the question. There is a possibility that one may read the union sign as intersection sign or vice versa which may lead us to an incorrect answer.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

The largest wind power cluster is located in the state class 11 social science CBSE

Explain zero factorial class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

What steps did the French revolutionaries take to create class 11 social science CBSE

Which among the following are examples of coming together class 11 social science CBSE

