Answer
Verified
478.2k+ views
Hint: In this question first assume any pair of linear equations in two variables and convert them into matrix format so use these concepts to reach the solution of the question.
Complete step-by-step answer:
Let us consider the system of linear equations in two variables be
$
ax + by = c \\
dx + ey = f \\
$
Where (x, y) are the variables and (a, b, c, d, e, f) are the constants.
Now convert this system of equation into matrix format we have,
$ \Rightarrow \left[ {\begin{array}{*{20}{c}}
a&b \\
d&e
\end{array}} \right]\left[ {\begin{array}{*{20}{c}}
x \\
y
\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}
c \\
f
\end{array}} \right]$
In above matrix format determinant (D) = $\left| {\begin{array}{*{20}{c}}
a&b \\
d&e
\end{array}} \right|$
So, the condition of unique solution of a pair of linear equation in two variables is
The value of determinant (D) should not equal zero.
$ \Rightarrow D \ne 0$
Or,
$D = \left| {\begin{array}{*{20}{c}}
a&b \\
d&e
\end{array}} \right| \ne 0$
Expand the determinant we have
$D = \left( {ae - bd} \right) \ne 0$
So, this is the required condition of a unique solution of a pair of linear equations in two variables.
So, this is the required answer.
Note: In such types of questions first let any two linear equations as above then convert it into matrix format as above and calculate the value of determinate so, for unique solution the value of determinant should not equal to zero if zero then the system of equations has either no solution or infinitely many solutions.
Complete step-by-step answer:
Let us consider the system of linear equations in two variables be
$
ax + by = c \\
dx + ey = f \\
$
Where (x, y) are the variables and (a, b, c, d, e, f) are the constants.
Now convert this system of equation into matrix format we have,
$ \Rightarrow \left[ {\begin{array}{*{20}{c}}
a&b \\
d&e
\end{array}} \right]\left[ {\begin{array}{*{20}{c}}
x \\
y
\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}
c \\
f
\end{array}} \right]$
In above matrix format determinant (D) = $\left| {\begin{array}{*{20}{c}}
a&b \\
d&e
\end{array}} \right|$
So, the condition of unique solution of a pair of linear equation in two variables is
The value of determinant (D) should not equal zero.
$ \Rightarrow D \ne 0$
Or,
$D = \left| {\begin{array}{*{20}{c}}
a&b \\
d&e
\end{array}} \right| \ne 0$
Expand the determinant we have
$D = \left( {ae - bd} \right) \ne 0$
So, this is the required condition of a unique solution of a pair of linear equations in two variables.
So, this is the required answer.
Note: In such types of questions first let any two linear equations as above then convert it into matrix format as above and calculate the value of determinate so, for unique solution the value of determinant should not equal to zero if zero then the system of equations has either no solution or infinitely many solutions.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Mark and label the given geoinformation on the outline class 11 social science CBSE
When people say No pun intended what does that mea class 8 english CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Give an account of the Northern Plains of India class 9 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
In Indian rupees 1 trillion is equal to how many c class 8 maths CBSE
Which are the Top 10 Largest Countries of the World?
How do you graph the function fx 4x class 9 maths CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Difference Between Plant Cell and Animal Cell
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Why is there a time difference of about 5 hours between class 10 social science CBSE