Answer
Verified
429k+ views
Hint: For the completion of any reaction we have to know about the reactivity of each species with another species. And we balance the chemical reaction by managing the molecularity of each atom to the reactant side as well as to the product side of the chemical reaction.
Complete answer:
Completion and balancing of above given reactions are as follow:
-Zinc (${\text{Zn}}$) on reacting with Hydrochloric acid produces Zinc chloride (${\text{ZnC}}{{\text{l}}_{\text{2}}}$) and hydrogen gas${\text{(}}{{\text{H}}_{\text{2}}})$and chemical reaction is display as follow:
${\text{Zn}}\left( {\text{s}} \right){\text{ + HCl}}\left( {{\text{aq}}} \right) \to {\text{ZnC}}{{\text{l}}_{\text{2}}}\left( {{\text{aq}}} \right){\text{ + }}{{\text{H}}_{\text{2}}}\left( {\text{g}} \right)$
And balanced form of the above reaction is as follow:
${\text{Zn}}\left( {\text{s}} \right){\text{ + 2HCl}}\left( {{\text{aq}}} \right) \to {\text{ZnC}}{{\text{l}}_{\text{2}}}\left( {{\text{aq}}} \right){\text{ + }}{{\text{H}}_{\text{2}}}\left( {\text{g}} \right)$
In which all species show the same molecularity on the left hand side as well as on the right hand side also.
-Sodium carbonate reacting with Hydrochloric acid produces sodium chloride solution, water and carbon dioxide gas. And chemical reaction is display as follow:
${\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left( {\text{s}} \right){\text{ + 2HCl}}\left( {{\text{aq}}} \right) \to {\text{NaCl}}\left( {{\text{aq}}} \right){\text{ + }}{{\text{H}}_{\text{2}}}{\text{O}}\left( {{\text{aq}}} \right){\text{ + C}}{{\text{O}}_{\text{2}}}\left( {\text{g}} \right)$
And balanced form of the above reaction is as follow:
${\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left( {\text{s}} \right){\text{ + 2HCl}}\left( {{\text{aq}}} \right) \to 2{\text{NaCl}}\left( {{\text{aq}}} \right){\text{ + }}{{\text{H}}_{\text{2}}}{\text{O}}\left( {{\text{aq}}} \right){\text{ + C}}{{\text{O}}_{\text{2}}}\left( {\text{g}} \right)$
In which all species show the same molecularity on the left hand side as well as on the right hand side also.
-Sodium bicarbonate reacting with Hydrochloric acid produces sodium chloride solution, water and carbon dioxide gas. And chemical reaction is display as follow:
${\text{NaHC}}{{\text{O}}_{\text{3}}}\left( {\text{s}} \right){\text{ + HCl}}\left( {{\text{aq}}} \right) \to {\text{NaCl}}\left( {{\text{aq}}} \right){\text{ + }}{{\text{H}}_{\text{2}}}{\text{O}}\left( {{\text{aq}}} \right){\text{ + C}}{{\text{O}}_{\text{2}}}\left( {\text{g}} \right)$
And the above reaction is present in the balanced form because all the species show the same molecularity on the left hand side as well as on the right hand side also.
-Sodium hydroxide on reacting with Hydrochloric acid produces sodium chloride solution and water and chemical reaction is display as follow:
${\text{NaOH}}\left( {{\text{aq}}} \right){\text{ + HCl}}\left( {{\text{aq}}} \right) \to {\text{NaCl}}\left( {{\text{aq}}} \right){\text{ + }}{{\text{H}}_{\text{2}}}{\text{O}}\left( {{\text{aq}}} \right)$
And the above reaction is present in the balanced form because all the species show the same molecularity on the left hand side as well as on the right hand side also.
-Copper oxide on reacting with hydrochloric acid produces copper ii chloride and water, and chemical reaction is display as follow:
${\text{CuO}}\left( {\text{s}} \right){\text{ + HCl}}\left( {{\text{aq}}} \right) \to {\text{CuC}}{{\text{l}}_{\text{2}}}\left( {\text{s}} \right){\text{ + }}{{\text{H}}_{\text{2}}}{\text{O}}\left( {{\text{aq}}} \right)$
And balanced form of the above reaction is as follow:
${\text{CuO}}\left( {\text{s}} \right){\text{ + 2HCl}}\left( {{\text{aq}}} \right) \to {\text{CuC}}{{\text{l}}_{\text{2}}}\left( {\text{s}} \right){\text{ + }}{{\text{H}}_{\text{2}}}{\text{O}}\left( {{\text{aq}}} \right)$
In which all species show the same molecularity on the left hand side as well as on the right hand side also.
Note:
Here some of you may write the wrong balanced equation, if you think that molecularity and oxidation state of any species is the same thing. So, always balanced the equation by keeping in mind that oxidation value and molecularity are different.
Complete answer:
Completion and balancing of above given reactions are as follow:
-Zinc (${\text{Zn}}$) on reacting with Hydrochloric acid produces Zinc chloride (${\text{ZnC}}{{\text{l}}_{\text{2}}}$) and hydrogen gas${\text{(}}{{\text{H}}_{\text{2}}})$and chemical reaction is display as follow:
${\text{Zn}}\left( {\text{s}} \right){\text{ + HCl}}\left( {{\text{aq}}} \right) \to {\text{ZnC}}{{\text{l}}_{\text{2}}}\left( {{\text{aq}}} \right){\text{ + }}{{\text{H}}_{\text{2}}}\left( {\text{g}} \right)$
And balanced form of the above reaction is as follow:
${\text{Zn}}\left( {\text{s}} \right){\text{ + 2HCl}}\left( {{\text{aq}}} \right) \to {\text{ZnC}}{{\text{l}}_{\text{2}}}\left( {{\text{aq}}} \right){\text{ + }}{{\text{H}}_{\text{2}}}\left( {\text{g}} \right)$
In which all species show the same molecularity on the left hand side as well as on the right hand side also.
-Sodium carbonate reacting with Hydrochloric acid produces sodium chloride solution, water and carbon dioxide gas. And chemical reaction is display as follow:
${\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left( {\text{s}} \right){\text{ + 2HCl}}\left( {{\text{aq}}} \right) \to {\text{NaCl}}\left( {{\text{aq}}} \right){\text{ + }}{{\text{H}}_{\text{2}}}{\text{O}}\left( {{\text{aq}}} \right){\text{ + C}}{{\text{O}}_{\text{2}}}\left( {\text{g}} \right)$
And balanced form of the above reaction is as follow:
${\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left( {\text{s}} \right){\text{ + 2HCl}}\left( {{\text{aq}}} \right) \to 2{\text{NaCl}}\left( {{\text{aq}}} \right){\text{ + }}{{\text{H}}_{\text{2}}}{\text{O}}\left( {{\text{aq}}} \right){\text{ + C}}{{\text{O}}_{\text{2}}}\left( {\text{g}} \right)$
In which all species show the same molecularity on the left hand side as well as on the right hand side also.
-Sodium bicarbonate reacting with Hydrochloric acid produces sodium chloride solution, water and carbon dioxide gas. And chemical reaction is display as follow:
${\text{NaHC}}{{\text{O}}_{\text{3}}}\left( {\text{s}} \right){\text{ + HCl}}\left( {{\text{aq}}} \right) \to {\text{NaCl}}\left( {{\text{aq}}} \right){\text{ + }}{{\text{H}}_{\text{2}}}{\text{O}}\left( {{\text{aq}}} \right){\text{ + C}}{{\text{O}}_{\text{2}}}\left( {\text{g}} \right)$
And the above reaction is present in the balanced form because all the species show the same molecularity on the left hand side as well as on the right hand side also.
-Sodium hydroxide on reacting with Hydrochloric acid produces sodium chloride solution and water and chemical reaction is display as follow:
${\text{NaOH}}\left( {{\text{aq}}} \right){\text{ + HCl}}\left( {{\text{aq}}} \right) \to {\text{NaCl}}\left( {{\text{aq}}} \right){\text{ + }}{{\text{H}}_{\text{2}}}{\text{O}}\left( {{\text{aq}}} \right)$
And the above reaction is present in the balanced form because all the species show the same molecularity on the left hand side as well as on the right hand side also.
-Copper oxide on reacting with hydrochloric acid produces copper ii chloride and water, and chemical reaction is display as follow:
${\text{CuO}}\left( {\text{s}} \right){\text{ + HCl}}\left( {{\text{aq}}} \right) \to {\text{CuC}}{{\text{l}}_{\text{2}}}\left( {\text{s}} \right){\text{ + }}{{\text{H}}_{\text{2}}}{\text{O}}\left( {{\text{aq}}} \right)$
And balanced form of the above reaction is as follow:
${\text{CuO}}\left( {\text{s}} \right){\text{ + 2HCl}}\left( {{\text{aq}}} \right) \to {\text{CuC}}{{\text{l}}_{\text{2}}}\left( {\text{s}} \right){\text{ + }}{{\text{H}}_{\text{2}}}{\text{O}}\left( {{\text{aq}}} \right)$
In which all species show the same molecularity on the left hand side as well as on the right hand side also.
Note:
Here some of you may write the wrong balanced equation, if you think that molecularity and oxidation state of any species is the same thing. So, always balanced the equation by keeping in mind that oxidation value and molecularity are different.
Recently Updated Pages
what is the correct chronological order of the following class 10 social science CBSE
Which of the following was not the actual cause for class 10 social science CBSE
Which of the following statements is not correct A class 10 social science CBSE
Which of the following leaders was not present in the class 10 social science CBSE
Garampani Sanctuary is located at A Diphu Assam B Gangtok class 10 social science CBSE
Which one of the following places is not covered by class 10 social science CBSE
Trending doubts
Which places in India experience sunrise first and class 9 social science CBSE
Which are the Top 10 Largest Countries of the World?
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
How do you graph the function fx 4x class 9 maths CBSE
In Indian rupees 1 trillion is equal to how many c class 8 maths CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Give 10 examples for herbs , shrubs , climbers , creepers
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Why is there a time difference of about 5 hours between class 10 social science CBSE