Question

How would you complete and balance the acid base neutralizations reaction: $HI + KOH \to ?$

Answer 1

Hint: The neutralization reaction is such a reaction where the acid reacts and neutralizes the base to form a salt product. During the reaction water is eliminated by the combination of hydrogen ion and hydroxide ion.

Complete step by step answer:
The acid-base reaction is also referred to as neutralization reaction. The neutralization reaction is defined as the reaction which takes place when the acid compound reacts with the base compound which as a result forms salt product by eliminating water. The water is formed by the combination of hydrogen ion ${H^ + }$ and hydroxide ion $O{H^ - }$ ion.
The general neutralization reaction is shown below.
$Acid + base \to Salt + water$
It is compulsory for all the acid and base to form salt on reaction and the by-product formed is the water.
When a strong acid will react with a weak base, then the salt formed will be an acidic salt. The pH of the salt will be less than 7.
When a strong acid will react with a strong base, then the salt formed will be neutral salt. The pH of the salt will be 7.
When a weak acid will react with a strong base, then the salt formed will be basic salt. The pH of the salt will be more than 7.
In the given question, the reaction is taking place between hydrogen iodide and potassium hydroxide.
The complete reaction is shown below.
$HI + KOH \to KI + {H_2}O$
In this reaction, the hydrogen iodide reacts with potassium hydroxide to form potassium iodide which is a salt and water.
The reaction is already balanced, as the number of atoms present on the reactant side is same as the atoms present in the product side.

Name of atom	Number in reactant side	Number in product side
H	2	2
I	1	1
K	1	1
O	1	1

Note:
The hydrogen iodide is a strong acid and potassium hydroxide is a strong base. So the product potassium iodide is a neutral salt and the pH will be 7.