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Last updated date: 01st Dec 2023
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MVSAT Dec 2023

Carbon- $14$ dating method is based on the fact that:
A.Ratio of carbon- $14$ and carbon- $12$ constant
B.Carbon-$14$ is the same in all objects
C.Carbon-$14$ is highly insoluble
D.All of these

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Hint: We have to know that, to address this question, you should review the ideas of radioactive rot of carbon- $14$ isotope in a dead natural matter. Carbon- $14$ is the heaviest of the three isotopes of carbon and it is radioactive in nature.

Complete answer:
We have to know that, the carbon- $14$ is the radioactive isotope of carbon and is known as radiocarbon. It is an exceptionally flimsy animal group and goes through radioactive rot not at all like the steady isotopes of carbon- $12$ and carbon- $13$, carbon-$14$ is set up in the air continually because of the activity of inestimable beams in the upper climate on nitrogen iotas. The carbon- $14$ subsequently framed oxidizes in a split second noticeable all around to shape carbon dioxide gas and enters the carbon cycle.
We have to see that this carbon- $14$ isotope from the carbon dioxide is absorbed throughout some stretch of time in all plants and creatures. At the point when the plant or creature bites the dust, the trading of carbon with the environment stops. The proportion of carbon- $12$ isotope and carbon- $14$ isotope in all living organic entities is consistent. At the point when the life form kicks the bucket, the degree of carbon- $12$ gets steady while that of carbon- $14$ declines in light of its radioactivity. By estimating the proportion of carbon- $12$ and carbon- $14$ in a given example and afterward contrasting it with that in a living life form, the age of the example can be resolved.

We have to know that, an isotope of a component is an animal variety that has a similar number of protons however an alternate number of neutrons. All in all, they are the molecules of a similar component having an alternate mass. There are three isotopic types of carbon, in particular, carbon- $12$, carbon- $13$ , and carbon- $14$.