Answer
Verified
335.1k+ views
Hint: If the standard EMF or the cell potential of the reaction between copper and iron is positive then the reaction will occur, if it is negative then the reaction will not occur. Reactivity of the element is based on the oxidation potential or reduction potential.
Complete answer:
The standard electrode potential of a large number of electrodes has been determined using a standard hydrogen electrode as the reference electrode.
The electrode at which reduction takes place concerning the standard hydrogen electrode has reduction potential and has a positive sign.
The electrode at which oxidation takes place concerning the standard hydrogen electrode has oxidation potential and has a negative sign.
The greater the oxidation potential or lower the reduction potential of metal, the more easily it can lose an electron and hence have greater reactivity. As a result, a metal with greater oxidation potential will displace the metal with lower oxidation potential from their salt.
Copper has a reduction potential of +0.34 V.
Iron has a reduction potential of -0.44 V.
So, the iron has lower reduction potential, it will be more reactive than iron. Therefore it will lose an electron. Copper having higher reduction potential will accept the electron and will change into solid copper.
The reaction will be:
$Fe(s)+CuS{{O}_{4}}(aq)\to FeS{{O}_{4}}+Cu$
Thus, iron will react with $CuS{{O}_{4}}$. Hence, we cannot store copper sulfate in an iron vessel.
Note: We can also find the standard EMF of the cell:
${{E}^{\circ }}_{F{{e}^{2+}},Fe}=-0.44V,\text{ }{{E}^{\circ }}_{C{{u}^{2+}},Cu}=+0.34V$
The reaction is:
$Fe(s)+CuS{{O}_{4}}(aq)\to FeS{{O}_{4}}+Cu$
The cell will be represented as: $Zn|Z{{n}^{2+}}||C{{u}^{2+}}|Cu$
${{E}^{\circ }}_{cell}={{E}^{\circ }}_{C{{u}^{2+}},Cu}-{{E}^{\circ }}_{F{{e}^{2+}},Fe}=+0.34V-(-0.44V)=0.78V$
As the EMF is positive the reaction will take place and we cannot store copper sulfate in an iron vessel.
Complete answer:
The standard electrode potential of a large number of electrodes has been determined using a standard hydrogen electrode as the reference electrode.
The electrode at which reduction takes place concerning the standard hydrogen electrode has reduction potential and has a positive sign.
The electrode at which oxidation takes place concerning the standard hydrogen electrode has oxidation potential and has a negative sign.
The greater the oxidation potential or lower the reduction potential of metal, the more easily it can lose an electron and hence have greater reactivity. As a result, a metal with greater oxidation potential will displace the metal with lower oxidation potential from their salt.
Copper has a reduction potential of +0.34 V.
Iron has a reduction potential of -0.44 V.
So, the iron has lower reduction potential, it will be more reactive than iron. Therefore it will lose an electron. Copper having higher reduction potential will accept the electron and will change into solid copper.
The reaction will be:
$Fe(s)+CuS{{O}_{4}}(aq)\to FeS{{O}_{4}}+Cu$
Thus, iron will react with $CuS{{O}_{4}}$. Hence, we cannot store copper sulfate in an iron vessel.
Note: We can also find the standard EMF of the cell:
${{E}^{\circ }}_{F{{e}^{2+}},Fe}=-0.44V,\text{ }{{E}^{\circ }}_{C{{u}^{2+}},Cu}=+0.34V$
The reaction is:
$Fe(s)+CuS{{O}_{4}}(aq)\to FeS{{O}_{4}}+Cu$
The cell will be represented as: $Zn|Z{{n}^{2+}}||C{{u}^{2+}}|Cu$
${{E}^{\circ }}_{cell}={{E}^{\circ }}_{C{{u}^{2+}},Cu}-{{E}^{\circ }}_{F{{e}^{2+}},Fe}=+0.34V-(-0.44V)=0.78V$
As the EMF is positive the reaction will take place and we cannot store copper sulfate in an iron vessel.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred
What is the stopping potential when the metal with class 12 physics JEE_Main
The momentum of a photon is 2 times 10 16gm cmsec Its class 12 physics JEE_Main
How do you arrange NH4 + BF3 H2O C2H2 in increasing class 11 chemistry CBSE
Is H mCT and q mCT the same thing If so which is more class 11 chemistry CBSE
Trending doubts
Difference Between Plant Cell and Animal Cell
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Summary of the poem Where the Mind is Without Fear class 8 english CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Write an application to the principal requesting five class 10 english CBSE
What organs are located on the left side of your body class 11 biology CBSE
What is the z value for a 90 95 and 99 percent confidence class 11 maths CBSE