Courses
Courses for Kids
Free study material
Offline Centres
More
Store

# Calculate total number of optical isomers in the following compounds:A ${\text{2}}$ B ${\text{4}}$ C ${\text{3}}$D ${\text{8}}$

Last updated date: 18th Jun 2024
Total views: 403.2k
Views today: 12.03k
Verified
403.2k+ views
Hint: So here in this question we have to calculate the total number of optical isomers. Basically, optical isomers are two compounds which contain the same number and kinds of atoms, and bonds which have non – superimposable mirror images.

So in this compound there are 4 optical isomers and these are calculated when we multiply the number of chiral centers by two.
Mathematically, to calculate the total no. of optical isomers is ${{\text{2}}^{{\text{n - 1}}}}$, where n is equal to the number of chiral centers. So as in this compound there are three chiral carbons. So here we consider, ${\text{n = 3}}$
So by substituting the value of n, we get,
${\text{ = }}{{\text{2}}^{{\text{3 - 1}}}}$
${\text{ = }}{{\text{2}}^{\text{2}}}$
${\text{ = 4}}$
Additional Information: For optical isomers, molecules that are having chiral centers:-
If n is even, then the number of enantiomers ${\text{ = }}{{\text{2}}^{{\text{n - 1}}}}$
No. of meso compounds ${\text{ = }}{{\text{2}}^{{\text{n}} / {\text{2 - 1}}}}$
Total no. of optical isomers ${\text{ = }}{{\text{2}}^{{\text{n - 1}}}}{\text{ + }}{{\text{2}}^{{\text{n}} / {\text{2 - 1}}}}$
That is; number of enantiomers + number of meso compounds =Total no. of optical isomers.
If n is odd, then the number of enantiomers ${\text{ = }}{{\text{2}}^{{\text{n - 1}}}}{\text{ - }}{{\text{2}}^{\left( {{\text{n - 1}}} \right)}}^{ / {\text{2}}}$
No. of meso compounds ${\text{ = }}{{\text{2}}^{\left( {{\text{n - 1}}} \right) / {\text{2}}}}$
Total no. of optical isomers ${\text{ = }}{{\text{2}}^{{\text{n - 1}}}}$
So here, meso compounds are non-optically active members at least two of which are optically active.
And there are 2n optical isomers for an organic molecule with n chiral centers.

So, the correct answer is Option B .

Note:
Working on carbons is chiral, so we just have to check each one separately. A chiral carbon is not a branched group. A chiral carbon is a carbon atom that is bonded to four different atoms.