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# Calculate the volume of wood of mass $6000$ kg when density of the wood is $0.8\,gc{m^3}$?

Last updated date: 16th Jul 2024
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Hint: The term "density" refers to the amount of mass per unit of volume.An object's average density is equal to its total mass divided by its total volume. An object made of a relatively dense material (such as iron) would have less volume than one made of a less dense substance of equal mass (such as water).

Density is the mass of a material substance per unit volume. Density is calculated using the formula $d = \dfrac{M}{V}$, where $d$ is density, $M$ is mass, and $V$ is volume. The density of a substance is usually measured in gram per cubic centimetre. Water, for example, has a density of $1$ gram per cubic centimetre, while the density of the Earth is $5.51$ gram per cubic centimetre. The kilogrammes per cubic metre unit of measurement is often used to express density.
The mass of the wood is $6000$ kg, and its density is $0.8$ gramme centimetre per cube, as stated in the problem.
$1\,L = 1000\,c{m^3}$
$\text{Volume} = \dfrac{\text{mass}}{\text{density}}$
Put m=$6000$ kg and Density =$0.8$ gram centimetre per cube into the equation.
$\text{Volume} = \dfrac{{6000}}{{\dfrac{{0.8}}{{1000}}}}$
$\therefore \text{Volume} = 7500\,L$
Hence, the wood has a volume of $7500$ L.