
Calcium amide on hydrolysis will give gas (B) which on oxidation by bleaching powder gives gas (C). Gas (C) on reaction with magnesium gives compound (D). (D) on hydrolysis gives again gas (B). (B), (C) and (D) respectively are.
A)$N{H_3}$,${N_2}$,$M{g_3}{N_2}$
B)${N_2}$,$N{H_3}$, $M{g_3}{N_2}$
C)${N_2}$,${N_2}{O_5}$, $Mg{(N{O_3})_2}$
D)$N{H_3}$,$N{O_2}$,$Mg{(N{O_2})_2}$
Answer
562.8k+ views
Hint: We have to remember that the hydrolysis of calcium imide at first gives the compound and which in turns gives a gas and a precipitate. The gas B which is formed is an important part in the agriculture sector because of its wide use in the Preparation of fertilizers.
Complete answer:
Let us see the reaction step so as to make sure that no mistakes are done while trying to point out the intermediated form as an end product of this series of reactions.
At first, calcium oxide is precipitated by the hydrolysis of calcium imide and ammonia is evolved into the surroundings. Hence the gas B which evolved during the reaction is ammonia.
We can write the chemical equation for this reaction as,
$CaNH + {H_2}O \to CaO \downarrow + N{H_3} \uparrow $
Next, Oxidation of evolved ammonia with bleaching powder gives calcium chloride precipitate and water and nitrogen gas is released to the surroundings. Thus the gas C which evolved during the reaction is Nitrogen. We can write the chemical equation for this reaction as,
$3CaOC{l_2} + 2N{H_3} \to 3CaC{l_2} \downarrow + 3{H_2}O + {N_2} \uparrow $
The third reaction is, if nitrogen evolved at the second step reacts with magnesium a magnesium nitride precipitate is formed as an end product. Hence the compound D which is formed during the reaction is magnesium nitride.
We can write the chemical equation for this reaction as,
$3Mg + {N_2} \to M{g_3}{N_2}$
The reaction which releases ammonia gas as a result of the hydrolysis of magnesium nitride is,
$M{g_3}{N_2} + 6{H_2}O \to 3Mg{\left( {OH} \right)_2} + 2N{H_3}$
Therefore, the correct option is A.
Note:
We have to know that a mixture of ammonia and bleaching powder is exceptionally perilous in light of the fact that poisonous fumes are delivered. The essential poisonous substance shaped by the response is chloramines fume which has the potential to frame hydrazine.
Complete answer:
Let us see the reaction step so as to make sure that no mistakes are done while trying to point out the intermediated form as an end product of this series of reactions.
At first, calcium oxide is precipitated by the hydrolysis of calcium imide and ammonia is evolved into the surroundings. Hence the gas B which evolved during the reaction is ammonia.
We can write the chemical equation for this reaction as,
$CaNH + {H_2}O \to CaO \downarrow + N{H_3} \uparrow $
Next, Oxidation of evolved ammonia with bleaching powder gives calcium chloride precipitate and water and nitrogen gas is released to the surroundings. Thus the gas C which evolved during the reaction is Nitrogen. We can write the chemical equation for this reaction as,
$3CaOC{l_2} + 2N{H_3} \to 3CaC{l_2} \downarrow + 3{H_2}O + {N_2} \uparrow $
The third reaction is, if nitrogen evolved at the second step reacts with magnesium a magnesium nitride precipitate is formed as an end product. Hence the compound D which is formed during the reaction is magnesium nitride.
We can write the chemical equation for this reaction as,
$3Mg + {N_2} \to M{g_3}{N_2}$
The reaction which releases ammonia gas as a result of the hydrolysis of magnesium nitride is,
$M{g_3}{N_2} + 6{H_2}O \to 3Mg{\left( {OH} \right)_2} + 2N{H_3}$
Therefore, the correct option is A.
Note:
We have to know that a mixture of ammonia and bleaching powder is exceptionally perilous in light of the fact that poisonous fumes are delivered. The essential poisonous substance shaped by the response is chloramines fume which has the potential to frame hydrazine.
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