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# How many $C$ atoms are there in $0.502{\text{ }}mole$ of $C$ ?

Last updated date: 23rd Jun 2024
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Hint: 1)Avogadro's number is a significant relationship to remember: $1{\text{ }}mole{\text{ }} =$ $6.022 \times {10^{23}}$ atoms, molecules, protons, and so forth
2)To change over from moles to atoms, multiply the molar sum by Avogadro's number

Avogadro's number is commonly dimensionless, yet when it defines the mole, it very well may be expressed as $6.022 \times {10^{23}}$ elementary entities/mol. This form shows the role of Avogadro's number as a conversion factor between the number of entities and the number of moles. Subsequently, given the relationship $1{\text{ }}mol{\text{ }} = {\text{ }}6.022{\text{ }}x{\text{ }}{10^{23}}$ atoms, changing over among moles and atoms of a substance becomes a simple dimensional analysis problem.
The quantity of atoms in a single mole of any substance is characterized by Avogadro's Number, a constant which is equivalent to $6.022 \times {10^{23}}$ , so there are roughly $6.022 \times {10^{23}}$ atoms in a single mole of a substance.
Number of C atoms = $5.02 \times$ $6.022 \times {10^{23}}$ = $3.0231147 \times$ ${10^{24}}$
Note: 1)The measure of substance of a system that contains as numerous elementary entities as there are atoms in $12{\text{ }}g$ of $carbon - 12$ .
2)Avogadro's number - The number of atoms present in $12{\text{ }}g$ of $carbon - 12$ , which is $6.022 \times {10^{23}}$ and the number of elementary entities (atoms or molecules) comprising one mole of a given substance.
3)From the moles of a substance, one can also locate the number of atoms in a sample and the other way around. The extension among atoms and moles is Avogadro's number, $6.022 \times {10^{23}}.$