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Bunky can walk \[3000\] feet in $ 10 $ minutes. Walking at the same rate, how many feet does she walk in $ 10 $ seconds?
 $ A) $ $ 50 $
 $ B) $ $ 70 $
 $ C) $ $ 40 $
 $ D) $ $ 30 $

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Answer
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Hint: First we have to define what the terms we need to solve the problem are.
Since Bunky has been walked \[3000\] feet in $ 10 $ minutes, we can now convert that minutes into the seconds, so that the required resultant answer is needed in the seconds only; hence converting minutes into seconds is one minute is equals sixty seconds that is $ 1\min = 60\sec $ . The given question is finding the walking for the $ 10 $ seconds at the same rate only.

Complete step by step answer:
Since we used the conversion technique for the minutes into seconds now, we will convert the $ 10 $ minutes into the seconds which is $ 10\min = (60 \times 10)\sec $ further solving we get; $ 10\min = 600\sec $
Now let Bunky walk \[3000\] feet in $ 10 $ minutes which is $ 600 $ seconds, now we will need to find at the same rate, how many feet that bunky has walked in only $ 10 $ seconds.
Since as we already know for $ 600 $ seconds the feet she walked so now we will need to find for same rate at $ 10 $ seconds, hence we will use the formula of the division which is dividend by divisor givens as the quotient, that means; $ \dfrac{{600}}{{60}} = 10 $ (six hundred is he travelled \[3000\] feet and ten seconds that we need to find hence I get it by dividing the term sixty)
Thus, dividing the term $ 60 $ will give as the result which is \[3000\] feet for ten seconds is $ \dfrac{{3000}}{{60}} = 50 $

So, the correct answer is “Option A”.

Note: we can also able to solve this problem using the speed formula that is $ speed = \dfrac{{dis\tan ce}}{{time}} $ Speed is the one that we will need to find it for the ten seconds and distance three thousand feet also the time given is ten minutes;
Since there is no possibility of getting options like $ B) $ $ 70 $ , $ C) $ $ 40 $ , $ D) $ $ 30 $ because if we divide correctly using the formula the only answer getable is option A. as fifty