Answer
424.5k+ views
Hint: Bond order is directly proportional to percentage s-character. The greater the s-character, the stronger the bond is. Conjugation in double bonds, imparts partial double bond character to single and double bonds.
Complete answer:
Butane is a hydrocarbon of alkane class with carbon atoms of hybridization of $s{{p}^{3}}$with normal C-C bond lengths. They have 25% s-character. The structure of butane molecule is given as follows:
And Butadiene is an alkene compound with 2 double bonds and the two double bonds are conjugated. The double bonds show conjugation, which increases the stability of the diene molecule. The molecule forms two resonating molecules. The carbon atoms have $s{{p}^{2}}$.
The double is conjugated between carbon-1 to carbon-3. The carbon-carbon bond in the centre of butadiene has a partial double bond character, due to which it is less than normal C-C bond length.The length of C-C bond is between single bond of C-C and double bond of C-C. The double bonds have 33% s-character, increased s-character increases, Bond order and decreases bond length. So percentage s-character is inversely proportional to bond length.
The percentage s-character of butane is less than butadiene , therefore , the bond length of the central carbon-carbon bond is more than that of butadiene.
Therefore, the Assertion is true, and the reason is the correct explanation of Assertion.
So, the correct answer is “Option A”.
Note: As s-character increases, electronegativity of carbon atom increases, bond angle, bond order increases and bond strength also increases. Since bond strength is increasing, bond enthalpy also increases.
Complete answer:
Butane is a hydrocarbon of alkane class with carbon atoms of hybridization of $s{{p}^{3}}$with normal C-C bond lengths. They have 25% s-character. The structure of butane molecule is given as follows:
![seo images](https://www.vedantu.com/question-sets/b3110297-b6d3-4ae7-b689-08f7d5880c5f3417962655079677838.png)
And Butadiene is an alkene compound with 2 double bonds and the two double bonds are conjugated. The double bonds show conjugation, which increases the stability of the diene molecule. The molecule forms two resonating molecules. The carbon atoms have $s{{p}^{2}}$.
![seo images](https://www.vedantu.com/question-sets/561f982d-49fd-449d-b170-5815bb3798524804669139283610128.png)
The double is conjugated between carbon-1 to carbon-3. The carbon-carbon bond in the centre of butadiene has a partial double bond character, due to which it is less than normal C-C bond length.The length of C-C bond is between single bond of C-C and double bond of C-C. The double bonds have 33% s-character, increased s-character increases, Bond order and decreases bond length. So percentage s-character is inversely proportional to bond length.
![seo images](https://www.vedantu.com/question-sets/59e88422-a47d-4a2b-865a-ab7c340b783d4259830315606201752.png)
The percentage s-character of butane is less than butadiene , therefore , the bond length of the central carbon-carbon bond is more than that of butadiene.
Therefore, the Assertion is true, and the reason is the correct explanation of Assertion.
So, the correct answer is “Option A”.
Note: As s-character increases, electronegativity of carbon atom increases, bond angle, bond order increases and bond strength also increases. Since bond strength is increasing, bond enthalpy also increases.
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