Question

As \[C{H_3} - Mg - Br\] is an organometallic compound due to :
a) \[Mg - Br\] bond
b) \[C - Mg\] bond
c) \[C - Br\] bond
d) \[C - H\] bond

Answer 1

Hint: For any compound to be an organometallic compound then there must be a direct bond between the carbon and the metallic atom . Also we know that metallic compounds are those which conduct electricity and show all the properties of an ideal metal.

Complete step-by-step answer:
Organometallic compound: it is basically defined as the chemical compounds that must contain one bond between the carbon atom that must belong to an organic molecule and a metal element belonging to any class. Such bonds are generally organic in nature.
Now we will talk about why the above equation \[C{H_3} - Mg - Br\] is organo metallic in nature.
Firstly we will talk about the \[Mg - Br\] bond
It is basically used as a Grignard reagent so this does not show the organo metallic bond.
Then we will talk about the \[C - Mg\] bond
Here,we can say that the bond is between a carbon and a magnesium that means the condition for organo metallic bond is being satisfied here as carbon is directly attached to the metallic element.
Then comes the \[C - Br\] bond
Here it does not satisfy the condition of the organometallic compound as carbon is directly attached to bromine but as we know that bromine is a halogen .
Then comes the \[C - H\] bond
This is a normal bond so further does not show organo metallic bond.
So hence,we conclude that the \[C - Mg\] bond organo metallic nature.
So, \[C{H_3} - Mg - Br\] is an organometallic compound due to \[C - Mg\].

Note: Must keep in mind that in organometallic compounds that the carbon should be directly attached to the metal atom and there should be no hindrance. . Further we should know that there are some related compounds such as transition metals and metal phosphine complexes are often discussed under this topic but they are not the ideal example to describe the organometallic complexes.