Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store

What are the materials required for the experiment to show chemical decomposition of water? Write the procedure of the experiment. Name the products we get in this reaction.

seo-qna
Last updated date: 20th Jun 2024
Total views: 396k
Views today: 3.96k
Answer
VerifiedVerified
396k+ views
Hint: To decompose very stable compounds like water electrolysis is a suitable method. When current is passed through the solution of a compound, it ionizes the compound and now these newly formed ions will move towards anode and cathode according to their charges. Positively charged ions will move towards cathode and negatively charged ions will move towards anode. At cathode positively charged ions will gain electrons and get discharged and at anode negatively charged ions lose the electron and get discharged.

Complete step by step solution:
Chemical decomposition of water will be done by electrolysis.
To perform electrolysis of water we need pencil, battery, electrolytic cell, connecting wire, distilled water, cardboard and very small quantities of acid.
seo images

- We will have the set up as shown in the diagram. We will fill the beaker with distilled water and with help of cardboard arrange the pencils as an electrode. Pencils will work as an electrode because their lead is made of graphite which is a good conductor of electricity. We will connect these graphite electrodes with the battery by using a connecting wire. Very small quantity of acid is used as a precursor for this electrolysis process.
- When we will switch on the battery and let the current pass, the following reaction in the acidic medium is going to take place.

At cathode: \[2{{H}^{+}}+2{{e}^{-}}\to {{H}_{2}}\]
At anode: $2{{H}_{2}}O\to {{O}_{2}}+4{{H}^{+}}+4{{e}^{-}}$
Net reaction: $2{{H}_{2}}O\to {{O}_{2}}+2{{H}_{2}}$
At cathode reduction of ${{H}^{+}}$ ion is taking place and ${{H}_{2}}$ gas is forming at cathode
At anode oxidation of $O{{H}^{-}}$ ion is taking place and ${{O}_{2}}$ gas is forming at anode.
So products in this reaction are ${{H}_{2}}$ and ${{O}_{2}}$

Additional Information:
Electrolysis of water can be done in the solution containing trace quantities of salts but for that salt selection is very important. Otherwise salt cation and anion will become competitors and themselves get discharged. Salts having lesser standard electrode potentials than hydrogen and hydroxide ions are suitable for the electrolysis of water.

Note: The efficiency of electrolysis or the electron transfer depends on many factors such as;
i) The number cations and anions in the solution
ii) Mobility of the ions
iii) Activation energy needed for the electron transfer from the electrode to the electrolyte ions.