
When we apply a force of $1\,N$, we can hold a body whose mass is approximately equal to
A. $100\,mg$
B. $100\,g$
C. $1\,kg$
D. $10\,kg$
Answer
409.5k+ views
Hint: Force is an external agent capable of changing the state of rest or motion of a particular body. It has a magnitude and a direction. The direction towards which the force is applied is known as the direction of the force and the application of force is the point where force is applied.
Complete step by step answer:
Given, $F = 1\,N$ and $g = 10\,m/{s^2}$. According to Newton's second law of Newton, the rate of change of momentum of an object is proportional to the applied force in the direction of the force. Where ‘F’ is applied force, ‘m’ is the mass of an object.
$F \propto \dfrac{{dv}}{{dt}}$
Change in velocity w.r.t. is known as acceleration.
$\dfrac{{dv}}{{dt}} = a$
So the following equation.
$F = ma$
$ \Rightarrow a = g$ Acceleration due to gravity.
Put given data in equation
$ F = mg$
$\Rightarrow m = \dfrac{F}{g}$
Put the value in equation
$m = \dfrac{{1\,N}}{{10\,m{s^{ - 2}}}} \\ $
$ \therefore m = 100\,g$
So the correct answer is option B.
Note: Force is the product of mass and acceleration. Application acceleration improves the application performances using techniques like compression, caching and transmission control protocol. When the velocity of any moving is changed it is said to be a change in acceleration. Change in acceleration may be positive or negative.
Complete step by step answer:
Given, $F = 1\,N$ and $g = 10\,m/{s^2}$. According to Newton's second law of Newton, the rate of change of momentum of an object is proportional to the applied force in the direction of the force. Where ‘F’ is applied force, ‘m’ is the mass of an object.
$F \propto \dfrac{{dv}}{{dt}}$
Change in velocity w.r.t. is known as acceleration.
$\dfrac{{dv}}{{dt}} = a$
So the following equation.
$F = ma$
$ \Rightarrow a = g$ Acceleration due to gravity.
Put given data in equation
$ F = mg$
$\Rightarrow m = \dfrac{F}{g}$
Put the value in equation
$m = \dfrac{{1\,N}}{{10\,m{s^{ - 2}}}} \\ $
$ \therefore m = 100\,g$
So the correct answer is option B.
Note: Force is the product of mass and acceleration. Application acceleration improves the application performances using techniques like compression, caching and transmission control protocol. When the velocity of any moving is changed it is said to be a change in acceleration. Change in acceleration may be positive or negative.
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