
An organic compound ‘X’ showing the following solubility profile is:
A) m-Cresol
B) o-Toluidine
C) Oleic acid
D) Benzamide
Answer
561.9k+ views
Hint: The answer here is based on the compound taken initially is a base or acid which later can be determined if it is soluble in another acid or base. The reaction of each option given with the reagents given leads you to the correct answer.
Complete step by step answer:
In the lower classes, we have studied the concepts in organic chemistry about the solubility of the compounds in acids or base or also neutral solutions.
Now, we shall look into each option and find whether the compound is soluble or insoluble in that particular reagent.
- Generally if X is a base, it would be soluble in acid but in the above given question, the compound does not react with both a weak base that is sodium hydroxide as well as a strong base that is sodium bicarbonate and gives an insoluble compound.
- By these above facts we can say that the compound is a weak acid because weak acid on treatment with strong base is insoluble whereas with weak base it reacts and the product is soluble.
- This weak acid with 10% $HCl$ will be insoluble and if we consider option A) m- Cresol which has methyl group in ortho position of phenol ring where –OH group is acidic.
- In option B) o-Tolidine, it is having an amine group and therefore is a base and thus this option is ruled out.
- In option C) Oleic acid has the formula ${{C}_{17}}{{H}_{33}}COOH$ which is strong acid than the m-Cresol because of presence of carboxylic acid group which is stronger that acidic –OH group.
- In option D) benzamide, it has a amide group which is also a base and thus is ruled out.
Therefore, based on all these facts, we can say that m-Cresol is a weak acid which is insoluble in water.
Therefore, the correct answer is option A) m-Cresol.
Note: Note that solubility of the compounds depends strongly on the pH of the solution and also the temperature as the solubility increases if the temperature is increased and this point is to be memorised which helps you to solve the questions asked on this basis.
Complete step by step answer:
In the lower classes, we have studied the concepts in organic chemistry about the solubility of the compounds in acids or base or also neutral solutions.
Now, we shall look into each option and find whether the compound is soluble or insoluble in that particular reagent.
- Generally if X is a base, it would be soluble in acid but in the above given question, the compound does not react with both a weak base that is sodium hydroxide as well as a strong base that is sodium bicarbonate and gives an insoluble compound.
- By these above facts we can say that the compound is a weak acid because weak acid on treatment with strong base is insoluble whereas with weak base it reacts and the product is soluble.
- This weak acid with 10% $HCl$ will be insoluble and if we consider option A) m- Cresol which has methyl group in ortho position of phenol ring where –OH group is acidic.
- In option B) o-Tolidine, it is having an amine group and therefore is a base and thus this option is ruled out.
- In option C) Oleic acid has the formula ${{C}_{17}}{{H}_{33}}COOH$ which is strong acid than the m-Cresol because of presence of carboxylic acid group which is stronger that acidic –OH group.
- In option D) benzamide, it has a amide group which is also a base and thus is ruled out.
Therefore, based on all these facts, we can say that m-Cresol is a weak acid which is insoluble in water.
Therefore, the correct answer is option A) m-Cresol.
Note: Note that solubility of the compounds depends strongly on the pH of the solution and also the temperature as the solubility increases if the temperature is increased and this point is to be memorised which helps you to solve the questions asked on this basis.
Recently Updated Pages
A man running at a speed 5 ms is viewed in the side class 12 physics CBSE

State and explain Hardy Weinbergs Principle class 12 biology CBSE

Which of the following statements is wrong a Amnion class 12 biology CBSE

Two Planoconcave lenses 1 and 2 of glass of refractive class 12 physics CBSE

The compound 2 methyl 2 butene on reaction with NaIO4 class 12 chemistry CBSE

Bacterial cell wall is made up of A Cellulose B Hemicellulose class 12 biology CBSE

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

Give 10 examples of unisexual and bisexual flowers

State the principle of an ac generator and explain class 12 physics CBSE

