Answer
Verified
396.3k+ views
Hint: The empirical relationship between temperature (\[T\]), volume (\[V\]), pressure (\[P\]) and no of moles of gas (\[n\]) is combining called as gas law or ideal gas equation.
Formula used:
Ideal gas equation
\[PV = nRT\],
Where,
\[n\]is number of moles, \[P\]is pressure, \[V\] (constant) is volume, \[T\] is temperature and \[R\] is the universal gas constant.
Complete step by step answer:
It is given that the volume of the container is \[V\], pressure is \[P\], stroke volume\[V\].
Let \[T\] be the temperature. Along with that we also know that,
\[\;v \ll V\]
We have to find the final pressure in the container after the n-strokes of the pump,
It is an isothermal process, thus \[T\]=constant,
Let in the first pump that is When\[n = 1\], volume \[V\] is reduced from the container then fractional change in volume is\[\dfrac{{\left( {V - v} \right)}}{V}\].
⟹\[\dfrac{{(V - v)}}{V}\]
Let us use the ideal gas equation which is as following,
\[PV = nRT\]
From the above equation we can write the following equation as,
\[P = n \times constant\] (as all other parameters are constant)
So from here we can conclude that the way number of moles will vary similarly pressure will vary,
Let us write the remaining number of moles as,
Number of moles = initial number of mole × fractional change in volume.
\[\;\;{N_1} = n \times \dfrac{{(V - v)}}{V}\] (1)
Similarly let us now write the pressure.
${P_1} = P \times \dfrac{{V - v}}{V}$
$ = P\left( {1 - \dfrac{v}{V}} \right)$ (2)
Now, after the second stroke the pressure is given below.
${P_2} = {P_1}\dfrac{{V - v}}{V}$
$ = P{\left( {1 - \dfrac{v}{V}} \right)^2}$ (3)
So in equation (2) and (3) we can observe a pattern. Hence let us write the pressure after n-number of strokes.
${P_n} = P{\left( {1 - \dfrac{v}{V}} \right)^n}$
Hence, pressure of the container after n strokes is$P{\left( {1 - \dfrac{v}{V}} \right)^n}$.
Additional information:
Apart from ideal gases, some gases don't obey the gas equation. Such gases are called real or non-ideal behaving gases.
For the real gases, the gas equation is modified by making changes in volume and pressure, which is given as follows,
$
\left( {P + \dfrac{{a{n^2}}}{{{V^2}}}} \right)(V - nb) = RTP \\
\\
$ , this is called the vander Waals equation.
\[P\]=pressure,
\[V\]=volume of gas
\[R\]=gas constant
$T$=Absolute temperature
$a,b$=Van der Waals constant
Note:
An isothermal process is a process in which we keep the temperature of the system constant.
For volume,$\dfrac{V}{{100}}$ , the final pressure in the container after nth stroke is, $P{\left( {\dfrac{{99}}{{100}}} \right)^n}$.
Formula used:
Ideal gas equation
\[PV = nRT\],
Where,
\[n\]is number of moles, \[P\]is pressure, \[V\] (constant) is volume, \[T\] is temperature and \[R\] is the universal gas constant.
Complete step by step answer:
It is given that the volume of the container is \[V\], pressure is \[P\], stroke volume\[V\].
Let \[T\] be the temperature. Along with that we also know that,
\[\;v \ll V\]
We have to find the final pressure in the container after the n-strokes of the pump,
It is an isothermal process, thus \[T\]=constant,
Let in the first pump that is When\[n = 1\], volume \[V\] is reduced from the container then fractional change in volume is\[\dfrac{{\left( {V - v} \right)}}{V}\].
⟹\[\dfrac{{(V - v)}}{V}\]
Let us use the ideal gas equation which is as following,
\[PV = nRT\]
From the above equation we can write the following equation as,
\[P = n \times constant\] (as all other parameters are constant)
So from here we can conclude that the way number of moles will vary similarly pressure will vary,
Let us write the remaining number of moles as,
Number of moles = initial number of mole × fractional change in volume.
\[\;\;{N_1} = n \times \dfrac{{(V - v)}}{V}\] (1)
Similarly let us now write the pressure.
${P_1} = P \times \dfrac{{V - v}}{V}$
$ = P\left( {1 - \dfrac{v}{V}} \right)$ (2)
Now, after the second stroke the pressure is given below.
${P_2} = {P_1}\dfrac{{V - v}}{V}$
$ = P{\left( {1 - \dfrac{v}{V}} \right)^2}$ (3)
So in equation (2) and (3) we can observe a pattern. Hence let us write the pressure after n-number of strokes.
${P_n} = P{\left( {1 - \dfrac{v}{V}} \right)^n}$
Hence, pressure of the container after n strokes is$P{\left( {1 - \dfrac{v}{V}} \right)^n}$.
Additional information:
Apart from ideal gases, some gases don't obey the gas equation. Such gases are called real or non-ideal behaving gases.
For the real gases, the gas equation is modified by making changes in volume and pressure, which is given as follows,
$
\left( {P + \dfrac{{a{n^2}}}{{{V^2}}}} \right)(V - nb) = RTP \\
\\
$ , this is called the vander Waals equation.
\[P\]=pressure,
\[V\]=volume of gas
\[R\]=gas constant
$T$=Absolute temperature
$a,b$=Van der Waals constant
Note:
An isothermal process is a process in which we keep the temperature of the system constant.
For volume,$\dfrac{V}{{100}}$ , the final pressure in the container after nth stroke is, $P{\left( {\dfrac{{99}}{{100}}} \right)^n}$.
Recently Updated Pages
Assertion The resistivity of a semiconductor increases class 13 physics CBSE
The branch of science which deals with nature and natural class 10 physics CBSE
What is the stopping potential when the metal with class 12 physics JEE_Main
The momentum of a photon is 2 times 10 16gm cmsec Its class 12 physics JEE_Main
How do you arrange NH4 + BF3 H2O C2H2 in increasing class 11 chemistry CBSE
Is H mCT and q mCT the same thing If so which is more class 11 chemistry CBSE
Trending doubts
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Difference Between Plant Cell and Animal Cell
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
What organs are located on the left side of your body class 11 biology CBSE
Write an application to the principal requesting five class 10 english CBSE
What is the type of food and mode of feeding of the class 11 biology CBSE
Name 10 Living and Non living things class 9 biology CBSE