Answer
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Hint:Volume of water after it freezes and becomes ice is the same as the volume of water before freezing. The water molecules come close to each other and form the lattice while melting the go away from each other and break the lattice.
Complete solution:
First we have to understand the situation. There is a glass ball inside an ice cube. This ice cube is put in the water and it floats on the surface. All these are in trough.
The above diagram shows the condition provided. Now you may think that the ice cube should sink and not float. This is because of a reason. The density of ice is less than that of water so it is not sinking. As the ball is stuck inside it the ball is not sinking.
Now if we see carefully the weight of the ice cube and glass ball together is balanced by the buoyant force acting on the body in upward direction.
So the ice cube with the glass ball inside it floats on the surface of the water.
Now if the ice melts, the volume now will be equal to the initial volume. As there is no considerable amount of water leaving or entering the trough.
So the total volume of the trough is not changed. Since the volume of water in solid state and that in liquid state is the same.
The glass ball’s volume was also included initially and so the net volume of the system is also not changed.
Thus option A is correct.
Note:If the cube was floating on the surface of water (with its lower face in contact with the surface) then the volume of the cube would have made a difference.
The net volume in that case would have changed and the water level would have increased.
Complete solution:
First we have to understand the situation. There is a glass ball inside an ice cube. This ice cube is put in the water and it floats on the surface. All these are in trough.
The above diagram shows the condition provided. Now you may think that the ice cube should sink and not float. This is because of a reason. The density of ice is less than that of water so it is not sinking. As the ball is stuck inside it the ball is not sinking.
Now if we see carefully the weight of the ice cube and glass ball together is balanced by the buoyant force acting on the body in upward direction.
So the ice cube with the glass ball inside it floats on the surface of the water.
Now if the ice melts, the volume now will be equal to the initial volume. As there is no considerable amount of water leaving or entering the trough.
So the total volume of the trough is not changed. Since the volume of water in solid state and that in liquid state is the same.
The glass ball’s volume was also included initially and so the net volume of the system is also not changed.
Thus option A is correct.
Note:If the cube was floating on the surface of water (with its lower face in contact with the surface) then the volume of the cube would have made a difference.
The net volume in that case would have changed and the water level would have increased.
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