Answer
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Hint:Chemical properties of an element are a function of its electronic configuration. The elements in a periodic table are arranged in such a way that the elements of the same group, will have similar chemical properties due to their identical outer shell configuration.
Complete step by step answer:
-When considering the Chemical property of an element, for example , the metallic character of an element.
-We say that elements which can easily lose electrons are more reactive metals.
-Using a similar logic, we say non metallic elements are those which can easily gain an electron.
-Notice the function of electrons in both these processes. Hence, it is possible to say that an element's chemical property is affected by its electrons.
-Now, only the outer shell electrons take part in any reaction , since the inner electrons are paired up.
-So, It is possible to say that, for elements which have the same chemical properties, will need to have similar electrons in their outer shell.
-Chlorine belongs to group 17 elements.
-They are also known as halogens .
-Group 17 include fluorine $F$ chlorine $Cl$, bromine $Br$, iodine $I$.
Chlorine having atomic number $17$ electronic configuration may be written as $1{s^2}2{s^2}2{p^6}3{s^2}3{p^5}$
Now , move to the solution part
-An element with atomic number $2$ is helium $He$ which belongs to group 18 noble gases.
-An element having atomic number $7$ and its electronic configuration may be written as $1{s^2}2{s^2}2{p^3}$ this means the element belongs to group 15 and the element is nitrogen $N$ .
-Element having atomic number $19$ its electronic configuration may be written as $1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}4{s^1}$ which belong to group 1 element and the element is potassium $K$.
-Element having atomic number 35 its electronic configuration may be written as $\left [{Ar} \right]183{d^{10}}4{s^2}4{p^5}$ which belong to group 17 and the element is bromine $Br$ .
-Element having atomic number 74 its electronic configuration may be written as $\left [{Xu} \right]544{f^{14}}5{d^4}6{s^2}$ which belong to d block element and the element is tungsten $W$.
-Hence, from the above it can be concluded that elements having atomic number 35 which is bromine show the same chemical property as chlorine because they both have the same outer shell electronic configuration.
Hence option D is the correct answer.
Note:
-In some case element from different group show same chemical properties because of diagonal relationship .For example lithium shows same property as magnesium this comes into existence because polarizing power being similar for the diagonally place element.it was revealed by an examination that the charge density of lithium is much closer to magnesium .
Complete step by step answer:
-When considering the Chemical property of an element, for example , the metallic character of an element.
-We say that elements which can easily lose electrons are more reactive metals.
-Using a similar logic, we say non metallic elements are those which can easily gain an electron.
-Notice the function of electrons in both these processes. Hence, it is possible to say that an element's chemical property is affected by its electrons.
-Now, only the outer shell electrons take part in any reaction , since the inner electrons are paired up.
-So, It is possible to say that, for elements which have the same chemical properties, will need to have similar electrons in their outer shell.
-Chlorine belongs to group 17 elements.
-They are also known as halogens .
-Group 17 include fluorine $F$ chlorine $Cl$, bromine $Br$, iodine $I$.
Chlorine having atomic number $17$ electronic configuration may be written as $1{s^2}2{s^2}2{p^6}3{s^2}3{p^5}$
Now , move to the solution part
-An element with atomic number $2$ is helium $He$ which belongs to group 18 noble gases.
-An element having atomic number $7$ and its electronic configuration may be written as $1{s^2}2{s^2}2{p^3}$ this means the element belongs to group 15 and the element is nitrogen $N$ .
-Element having atomic number $19$ its electronic configuration may be written as $1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}4{s^1}$ which belong to group 1 element and the element is potassium $K$.
-Element having atomic number 35 its electronic configuration may be written as $\left [{Ar} \right]183{d^{10}}4{s^2}4{p^5}$ which belong to group 17 and the element is bromine $Br$ .
-Element having atomic number 74 its electronic configuration may be written as $\left [{Xu} \right]544{f^{14}}5{d^4}6{s^2}$ which belong to d block element and the element is tungsten $W$.
-Hence, from the above it can be concluded that elements having atomic number 35 which is bromine show the same chemical property as chlorine because they both have the same outer shell electronic configuration.
Hence option D is the correct answer.
Note:
-In some case element from different group show same chemical properties because of diagonal relationship .For example lithium shows same property as magnesium this comes into existence because polarizing power being similar for the diagonally place element.it was revealed by an examination that the charge density of lithium is much closer to magnesium .
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