
An element along with its atomic number and mass number is represented as ${}_Z{X^A}$ where $X$ is the symbol of the element, $Z$ is the atomic number and \[A\]is the mass number Represent elements\[A\], \[B\], \[C\],$D$ and $E$ with its atomic number and mass number from the given data.
Elements Number of protons Number of electrons Number of neutrons \[A\] \[x\] \[y\] \[B\] \[a\] \[b\] \[C\] \[m\] $m + 2$ $D$ \[t\] \[t\] $E$ \[n\] $n + 1$
Elements | Number of protons | Number of electrons | Number of neutrons |
\[A\] | \[x\] | \[y\] | |
\[B\] | \[a\] | \[b\] | |
\[C\] | \[m\] | $m + 2$ | |
$D$ | \[t\] | \[t\] | |
$E$ | \[n\] | $n + 1$ |
Answer
466.8k+ views
Hint: The number of protons and electrons in any element is the same since the element has to be electrically neutral. Mass number of an element is the sum of the number of protons and number of neutrons and it is written as superscript on the element symbol.
Complete step by step answer:
Number of neutrons = atomic mass number - atomic number of protons = number of electronsNumber of protons is equal to the atomic number. So according to formula we can represent
Element \[A\]is represented as ${}_x{A^{y + x}}$
Atomic number ($Z$) = \[x\]
Atomic mass ($A$) =$y + x$
As we know number of protons is equal to number of electron so the unknown box in element \[A\] is \[x\]
Element \[B\] is represented ${}_a{B^{a + b}}$
Atomic number ($Z$) = $a$
Atomic mass ($A$) =$a + b$
As we know number of protons is equal to number of electron so the unknown box in element \[B\] is \[{\mathbf{a}}\]
Element \[C\] is represented ${}_m{C^{2m + 2}}$
Atomic number ($Z$) =$m$
Atomic mass ($A$) =$2m + 2$
As we know number of protons is equal to number of electron so the unknown box in element \[C\] is \[{\mathbf{m}}\]
Element \[D\] is represented ${}_t{D^{2t}}$
Atomic number ($Z$) =$t$
Atomic mass ($A$) =$2t$
As we know number of protons is equal to number of electron so the unknown box in element $D$ is \[{\mathbf{t}}\]
Element \[E\] is represented ${}_n{E^{2n + 1}}$
Atomic number ($Z$) =$n$
Atomic mass ($A$) =$2n + 1$
As we know number of protons is equal to number of electron so the unknown box in element is \[E\] is \[{\mathbf{n}}\]
Additional information:
The mass of an atom of an element expressed in mass units. It's approximately like the amount of protons and neutrons within the atom (the mass number) or to the typical number allowing the relative abundances of various
The number of protons within the nucleus of an atom, which is characteristic of a element and determines its place within the table
Protons are charged ,neutrons are uncharged and electrons are charged . The charge of \[1\] electron balances the charge of \[1\] proton
The negative charge of one electron balances the positive charge of one proton
Note: Isotopes have the same number of electrons, which means they will also have the same number of protons. They only differ in the number of neutrons. Hence, the element can have the same atomic number but different mass number.
Complete step by step answer:
Number of neutrons = atomic mass number - atomic number of protons = number of electronsNumber of protons is equal to the atomic number. So according to formula we can represent
Element \[A\]is represented as ${}_x{A^{y + x}}$
Atomic number ($Z$) = \[x\]
Atomic mass ($A$) =$y + x$
As we know number of protons is equal to number of electron so the unknown box in element \[A\] is \[x\]
Element \[B\] is represented ${}_a{B^{a + b}}$
Atomic number ($Z$) = $a$
Atomic mass ($A$) =$a + b$
As we know number of protons is equal to number of electron so the unknown box in element \[B\] is \[{\mathbf{a}}\]
Element \[C\] is represented ${}_m{C^{2m + 2}}$
Atomic number ($Z$) =$m$
Atomic mass ($A$) =$2m + 2$
As we know number of protons is equal to number of electron so the unknown box in element \[C\] is \[{\mathbf{m}}\]
Element \[D\] is represented ${}_t{D^{2t}}$
Atomic number ($Z$) =$t$
Atomic mass ($A$) =$2t$
As we know number of protons is equal to number of electron so the unknown box in element $D$ is \[{\mathbf{t}}\]
Element \[E\] is represented ${}_n{E^{2n + 1}}$
Atomic number ($Z$) =$n$
Atomic mass ($A$) =$2n + 1$
As we know number of protons is equal to number of electron so the unknown box in element is \[E\] is \[{\mathbf{n}}\]
Elements | Number of protons | Number of electrons | Number of neutrons |
\[A\] | \[x\] | \[x\] | \[y\] |
\[B\] | \[a\] | \[a\] | \[b\] |
\[C\] | \[m\] | \[m \] | $m + 2$ |
$D$ | \[t\] | \[t\] | \[t\] |
$E$ | \[n\] | \[n\] | $n + 1$ |
Additional information:
The mass of an atom of an element expressed in mass units. It's approximately like the amount of protons and neutrons within the atom (the mass number) or to the typical number allowing the relative abundances of various
The number of protons within the nucleus of an atom, which is characteristic of a element and determines its place within the table
Protons are charged ,neutrons are uncharged and electrons are charged . The charge of \[1\] electron balances the charge of \[1\] proton
The negative charge of one electron balances the positive charge of one proton
Note: Isotopes have the same number of electrons, which means they will also have the same number of protons. They only differ in the number of neutrons. Hence, the element can have the same atomic number but different mass number.
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

The correct geometry and hybridization for XeF4 are class 11 chemistry CBSE

Water softening by Clarks process uses ACalcium bicarbonate class 11 chemistry CBSE

With reference to graphite and diamond which of the class 11 chemistry CBSE

Trending doubts
10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

State and prove Bernoullis theorem class 11 physics CBSE

What organs are located on the left side of your body class 11 biology CBSE

How many valence electrons does nitrogen have class 11 chemistry CBSE
