Akira gave a problem to her sister Kiara. However, Kiara got stuck. Help Kiara identify whether the triangles are congruent and choose the correct option.
A. Yes, $\Delta ABC \cong \Delta DCE$
B. No, they are not congruent
C. Yes, $\Delta DCE \cong \Delta BAC$
D. Yes. $\Delta DCE \cong \Delta CAB$
Answer
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Hint: According to the given figure, we will that see the sides are equal. Therefore we will take two triangles $\Delta CAB\,and\,\,\Delta DEC$ and will prove by SSS Criterion.
Complete step-by-step answer:
In the given figure
$AB = BE = EC = MD = MC$
$AC = DE$
And $DC = DM + MC$ …… (i)
Also $BC = BE + EC$ …… (ii)
Now, from equation (ii) we will replace $BE = MD$and $EC = MC$ then
$BC = MD + MC$ ….. (iii)
$DC = DM + MC$ ……. (iv)
Then from equation (iii) and (iv), we will get
$BC = DC$
Now, in $\Delta DCE\,\,and\,\,\Delta CAB,$
$DC = CB$ (proved above)
$DE = CA$ (given)
$CE = AB$ (given)
$\therefore \Delta DCE \cong \Delta CAB$ (SS Criterion)
Hence, the correct option is D.
Additional information: There are five ways to find if two triangles are congruent.
1. SSS: - We have two triangles with all three sides equal.
2. SAS: - We have two triangles where we know two sides and the included angle are equal.
3. ASA: - We have two triangles where we know two angles and the included sides are equal.
4. AAS: We have two triangles where we know two angles and the non-included sides are equal.
5. RHS: - We have two right-angled triangles with the same length of hypotenuse and same lengths for one of the other two sides.
Note: Students must keep in mind that if three sides of one triangle are equal to the corresponding three sides of another triangle then both triangles are congruent by SSS rule.
Complete step-by-step answer:
In the given figure
$AB = BE = EC = MD = MC$
$AC = DE$
And $DC = DM + MC$ …… (i)
Also $BC = BE + EC$ …… (ii)
Now, from equation (ii) we will replace $BE = MD$and $EC = MC$ then
$BC = MD + MC$ ….. (iii)
$DC = DM + MC$ ……. (iv)
Then from equation (iii) and (iv), we will get
$BC = DC$
Now, in $\Delta DCE\,\,and\,\,\Delta CAB,$
$DC = CB$ (proved above)
$DE = CA$ (given)
$CE = AB$ (given)
$\therefore \Delta DCE \cong \Delta CAB$ (SS Criterion)
Hence, the correct option is D.
Additional information: There are five ways to find if two triangles are congruent.
1. SSS: - We have two triangles with all three sides equal.
2. SAS: - We have two triangles where we know two sides and the included angle are equal.
3. ASA: - We have two triangles where we know two angles and the included sides are equal.
4. AAS: We have two triangles where we know two angles and the non-included sides are equal.
5. RHS: - We have two right-angled triangles with the same length of hypotenuse and same lengths for one of the other two sides.
Note: Students must keep in mind that if three sides of one triangle are equal to the corresponding three sides of another triangle then both triangles are congruent by SSS rule.
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