
Air contains nitrogen and oxygen in the volume ratio of 4:1 .The average vapour density of air is :
A.30
B.28.8
C.28
D.14.4
Answer
553.2k+ views
Hint:Nitrogen and oxygen are present by volume , so first we will calculate the total molecular mass of air. We will then keep this valve of molecular mass in the vapour density formula and calculate the value of vapour density.
Complete step by step answer:
Nitrogen and oxygen are present in the volume ratio of 4:1 . It means 80% nitrogen and 20% oxygen are present in the gas.
Vapour Density of a gas is the relative ratio of the density of that gas to that of density of hydrogen gas. Mathematically,
Vapour density =$\dfrac{{density(gas)}}{{density({H_2})}}$.
We will use this equation to procced through the question. We will now learn to calculate density of a gas.
From ideal gas equation we have,
$
PV = nRT \\
PV = \dfrac{w}{M}RT \\
\dfrac{{PM}}{{RT}} = \dfrac{w}{V} \\
$
Where
$
P = pressure \\
V = volume \\
T = temperature \\
n = moles \\
$
Since ,
$\dfrac{w}{V} = density(gas)$
We can rewrite the above equation as ${d_{gas}} = \dfrac{{PM}}{{RT}}$……….(i) . This is the general equation of calculating the density of any gas. Keeping all other factors constant , density depends on molecular mass of gas i.e. $M$.
We can now write it as :
Vapour density = $\dfrac{{{d_{gas}}}}{{{d_{{H_2}}}}} = \dfrac{{{M_{gas}}}}{{{M_{{H_2}}}}}$.
Since the molecular mass of hydrogen gas is 2. The equation gets reduced to-
$VD = \dfrac{{{M_{gas}}}}{2}$…………(ii)
We will now calculate the molecular mass of the gas.
${M_{gas}} = \dfrac{{80}}{{100}} \times m({N_2}) + \dfrac{{20}}{{100}} \times m({O_2})$
$
{M_{gas}} = \dfrac{4}{5} \times 28 + \dfrac{1}{5} \times 32 \\
{M_{gas}} = 22.4 + 6.4 \\
{M_{gas}} = 28.8 \\
\\
$
We know the relation between density and molecular mass . Now using that:
From equation (ii),
$
VD = \dfrac{{{M_{gas}}}}{2} \\
VD = \dfrac{{28.8}}{2} \\
VD = 14.4 \\
$
Hence, option (D) is correct.
Note: Vapour density is a unitless quantity . Vapour density is only calculated for gas and vapour. There are only 14 gases and vapour with a vapour density less than one, i.e. they are lighter than air. The density and vapour density of a gas are not the same. More the vapour density of a gas, the heavier the gas will be.
Complete step by step answer:
Nitrogen and oxygen are present in the volume ratio of 4:1 . It means 80% nitrogen and 20% oxygen are present in the gas.
Vapour Density of a gas is the relative ratio of the density of that gas to that of density of hydrogen gas. Mathematically,
Vapour density =$\dfrac{{density(gas)}}{{density({H_2})}}$.
We will use this equation to procced through the question. We will now learn to calculate density of a gas.
From ideal gas equation we have,
$
PV = nRT \\
PV = \dfrac{w}{M}RT \\
\dfrac{{PM}}{{RT}} = \dfrac{w}{V} \\
$
Where
$
P = pressure \\
V = volume \\
T = temperature \\
n = moles \\
$
Since ,
$\dfrac{w}{V} = density(gas)$
We can rewrite the above equation as ${d_{gas}} = \dfrac{{PM}}{{RT}}$……….(i) . This is the general equation of calculating the density of any gas. Keeping all other factors constant , density depends on molecular mass of gas i.e. $M$.
We can now write it as :
Vapour density = $\dfrac{{{d_{gas}}}}{{{d_{{H_2}}}}} = \dfrac{{{M_{gas}}}}{{{M_{{H_2}}}}}$.
Since the molecular mass of hydrogen gas is 2. The equation gets reduced to-
$VD = \dfrac{{{M_{gas}}}}{2}$…………(ii)
We will now calculate the molecular mass of the gas.
${M_{gas}} = \dfrac{{80}}{{100}} \times m({N_2}) + \dfrac{{20}}{{100}} \times m({O_2})$
$
{M_{gas}} = \dfrac{4}{5} \times 28 + \dfrac{1}{5} \times 32 \\
{M_{gas}} = 22.4 + 6.4 \\
{M_{gas}} = 28.8 \\
\\
$
We know the relation between density and molecular mass . Now using that:
From equation (ii),
$
VD = \dfrac{{{M_{gas}}}}{2} \\
VD = \dfrac{{28.8}}{2} \\
VD = 14.4 \\
$
Hence, option (D) is correct.
Note: Vapour density is a unitless quantity . Vapour density is only calculated for gas and vapour. There are only 14 gases and vapour with a vapour density less than one, i.e. they are lighter than air. The density and vapour density of a gas are not the same. More the vapour density of a gas, the heavier the gas will be.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
Differentiate between an exothermic and an endothermic class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

