 According to the Bohr-Bury scheme, the maximum number of electrons which can be accommodated in a given shell is given by the formula:A.$2{{\text{n}}^{2}}$B.${{\text{n}}^{\text{2}}}$C.$\text{3}{{\text{n}}^{2}}$D.$2\text{n}$ Verified
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Hint:The distribution of the electrons in the orbits or the shells of the atoms is governed by the Bohr-Bury Scheme. The arrangement of the electrons in various energy levels of an atom is called the electronic configuration of the atom.

-In general the total or the maximum number of electrons that can be accommodated in a shell is equal to $2{{\text{n}}^{2}}$, where n is the shell number or the principal quantum number.
For the K-shell, n = 1, putting the value of n in the above formula we get, the number of electrons that can accommodate the K-shell is $2{{\left( 1 \right)}^{2}}=2$. For the L-shell, n = 2, hence putting the value in the formula we get, $2{{\left( 2 \right)}^{2}}=8$, so the second shell can accommodate eight electrons and so on. The outermost shell of the atom cannot have more than eight electrons; the arrangement of the electrons in the shell is arranged in different orbitals.