Answer
Verified
415.5k+ views
Hint: Rectangle: a quadrilateral in which opposite sides are parallel and equal and all of the angles are ${90^ \circ }$ Square: A square is a quadrilateral in which all four sides are equal where both pairs of opposite sides are parallel and all angles are ${90^ \circ }$.
Complete step-by-step answer:
Proof: In $\Delta ABC$ and $\Delta ADC$
$\angle BAC = \angle DAC$ ($AC$ bisects $\angle A$)
$\angle BCA = \angle DCA$ ($AC$ bisects $\angle C$)
$AC = AC$ (common)
Therefore by Angle-Side-Angle Congruence, the triangles are congruent.
Therefore, by using congruent parts of congruent triangles (CPCT), we can say that,
$AB = AD$
And,$CB = CD$.
But, we know that, In a rectangle opposite sides are equal,
Therefore,
$AB = DC$ and $BC = AD$
Therefore by taking all the conditions proved above we can say that,
$AB = BC = CD = AD$
Since, all the four sides are proved to be equal, therefore, we can say that it is a square.
Hence Proved!
Proof: In $\Delta ABD$ and $\Delta CDB$
$AD = CB$(Equal sides of square)
$AB = CD$ (Equal sides of square)
$BD = BD$ (Common)
Therefore by side-side-side congruence, the triangles are congruent.
Therefore, by using congruent parts of congruent triangles (CPCT), we can say that,
$\angle ABD = \angle CBD$ and,
$\angle ADB = \angle CDB$
Therefore, we can say that diagonal $BD$ bisects $\angle B$ as well as$\angle D$.
Note: Make sure you write the reason in the bracket for the statements you write while proving the congruence.
Complete step-by-step answer:
Proof: In $\Delta ABC$ and $\Delta ADC$
$\angle BAC = \angle DAC$ ($AC$ bisects $\angle A$)
$\angle BCA = \angle DCA$ ($AC$ bisects $\angle C$)
$AC = AC$ (common)
Therefore by Angle-Side-Angle Congruence, the triangles are congruent.
Therefore, by using congruent parts of congruent triangles (CPCT), we can say that,
$AB = AD$
And,$CB = CD$.
But, we know that, In a rectangle opposite sides are equal,
Therefore,
$AB = DC$ and $BC = AD$
Therefore by taking all the conditions proved above we can say that,
$AB = BC = CD = AD$
Since, all the four sides are proved to be equal, therefore, we can say that it is a square.
Hence Proved!
Proof: In $\Delta ABD$ and $\Delta CDB$
$AD = CB$(Equal sides of square)
$AB = CD$ (Equal sides of square)
$BD = BD$ (Common)
Therefore by side-side-side congruence, the triangles are congruent.
Therefore, by using congruent parts of congruent triangles (CPCT), we can say that,
$\angle ABD = \angle CBD$ and,
$\angle ADB = \angle CDB$
Therefore, we can say that diagonal $BD$ bisects $\angle B$ as well as$\angle D$.
Note: Make sure you write the reason in the bracket for the statements you write while proving the congruence.
Recently Updated Pages
Assertion The resistivity of a semiconductor increases class 13 physics CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
How do you arrange NH4 + BF3 H2O C2H2 in increasing class 11 chemistry CBSE
Is H mCT and q mCT the same thing If so which is more class 11 chemistry CBSE
What are the possible quantum number for the last outermost class 11 chemistry CBSE
Is C2 paramagnetic or diamagnetic class 11 chemistry CBSE
Trending doubts
Difference Between Plant Cell and Animal Cell
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Summary of the poem Where the Mind is Without Fear class 8 english CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Write an application to the principal requesting five class 10 english CBSE
What organs are located on the left side of your body class 11 biology CBSE
What is the z value for a 90 95 and 99 percent confidence class 11 maths CBSE