Courses
Courses for Kids
Free study material
Offline Centres
More

# A vessel with water is placed on a weighing pan and it reads $600$gm. Now, a ball of mass $40$gm and density $0.80g/c{{m}^{-3}}$is sunk into the water with a pin of negligible volume, as shown in figure. The weighing pan will show a reading:a)$600gm$b)$550gm$c)$650gm$d)$632gm$

Last updated date: 03rd Mar 2024
Total views: 340.2k
Views today: 7.40k
Verified
340.2k+ views
Hint: Calculate the volume of the ball given and then find out the weight of it. Then, add it up with the existing weight. Also, the mass of the pin is negligible, neglecting the weight of it in the total measurement. Weight and mass are not the same.
Formula used:
$d=\dfrac{m}{v}$

Let us assume the density of the given ball is $d$, the mass of the ball as $m$and the volume of the ball as $v$. Now, the volume of the ball must be calculated,
\begin{align} & d=\dfrac{m}{v} \\ & v=\dfrac{m}{d} \\ & v=\dfrac{40}{0.80} \\ & v=50c{{m}^{3}} \\ \end{align}
Now, the total weight must be calculated in the following way,
total weight =
\begin{align} & 600+50 \\ & 650 \\ \end{align}

Therefore, the weighing pan will display as $650$, option c.