
A solution of 500 ml of 0.2 M KOH and 500 ml of 0.2M HCl is mixed and stirred, the rise in temperature is ${{T}_{1}}$. The experiment is repeated using 250 ml each of solution, the temperature rise is ${{T}_{2}}$, which of the following is true?
A) ${{T}_{1}} = {{T}_{2}}$
B) ${{T}_{1}} = 2{{T}_{2}}$
C) ${{T}_{1}} = 4{{T}_{2}}$
D) ${{T}_{2}} = 9{{T}_{1}}$
Answer
550.8k+ views
Hint:. The temperature difference can be calculated using the equation, $Q = m{{C}_{V}}\Delta T$
- Where Q is the heat and n is the number of moles, ${{C}_{V}}$ is the specific heat capacity of a substance and $\Delta T$ is the change in temperature.
Complete step by step answer:
In the question, it is given than a solution of 500 ml of 0.2 M KOH and 500 ml of 0.2 M HCl is mixed and the temperature during the reaction is noted as ${{T}_{1}}$ and then another reaction is carried out by mixing 250 ml of KOH and 250 ml of HCl solution of 0.2 M and change in temperature can be calculated ie${{T}_{2}}$.
The reaction involved here is,
$KOH+HCl\to KCl+{{H}_{2}}O$
For finding the moles we can use the equation,
No. of moles =Molarity of the solution $\times$ Volume of the solution
Here the molarity of the solution is taken as 0.2 M as both the solutions have the same molarity and the volume of the solution is 500 ml.
No. of moles = 0.2 $\times$ 500 = 100
As in the question, ${{C}_{V}}$ is not given we eliminate the term and rewrite the equation as, $Q=n\Delta T$
For ${{Q}_{1}}$, ${{Q}_{1}} = n\Delta T = 100\times {{T}_{1}} = 100{{T}_{1}}$
Molarity of the solution is 0.2M and the volume of the solution is 250ml.
No. of moles = 0.2$\times$250 = 50
For${{Q}_{2}}$,${{Q}_{2}} = n\Delta T= 50\times {{T}_{2}} = 50{{T}_{2}}$
From the equations obtained we can say that the ${{Q}_{1}} = 2{{Q}_{2}}$
${{Q}_{1}} = 2{{Q}_{2}}$
$100{{T}_{1}} = 2\times 50{{T}_{2}}$
$100{{T}_{1}} = 100{{T}_{2}}$
${{T}_{1}} = {{T}_{2}}$
So, the correct answer is “Option A”.
Note: If mass is given in the question, then we can alter the equation as,$Q = m{{C}_{V}}\Delta T$
Where m is the mass of the substance given in the question.
- And for such problems the value for specific heat capacity of the substance ${{C}_{V}}$, will be provided in the question.
- Where Q is the heat and n is the number of moles, ${{C}_{V}}$ is the specific heat capacity of a substance and $\Delta T$ is the change in temperature.
Complete step by step answer:
In the question, it is given than a solution of 500 ml of 0.2 M KOH and 500 ml of 0.2 M HCl is mixed and the temperature during the reaction is noted as ${{T}_{1}}$ and then another reaction is carried out by mixing 250 ml of KOH and 250 ml of HCl solution of 0.2 M and change in temperature can be calculated ie${{T}_{2}}$.
The reaction involved here is,
$KOH+HCl\to KCl+{{H}_{2}}O$
For finding the moles we can use the equation,
No. of moles =Molarity of the solution $\times$ Volume of the solution
Here the molarity of the solution is taken as 0.2 M as both the solutions have the same molarity and the volume of the solution is 500 ml.
No. of moles = 0.2 $\times$ 500 = 100
As in the question, ${{C}_{V}}$ is not given we eliminate the term and rewrite the equation as, $Q=n\Delta T$
For ${{Q}_{1}}$, ${{Q}_{1}} = n\Delta T = 100\times {{T}_{1}} = 100{{T}_{1}}$
Molarity of the solution is 0.2M and the volume of the solution is 250ml.
No. of moles = 0.2$\times$250 = 50
For${{Q}_{2}}$,${{Q}_{2}} = n\Delta T= 50\times {{T}_{2}} = 50{{T}_{2}}$
From the equations obtained we can say that the ${{Q}_{1}} = 2{{Q}_{2}}$
${{Q}_{1}} = 2{{Q}_{2}}$
$100{{T}_{1}} = 2\times 50{{T}_{2}}$
$100{{T}_{1}} = 100{{T}_{2}}$
${{T}_{1}} = {{T}_{2}}$
So, the correct answer is “Option A”.
Note: If mass is given in the question, then we can alter the equation as,$Q = m{{C}_{V}}\Delta T$
Where m is the mass of the substance given in the question.
- And for such problems the value for specific heat capacity of the substance ${{C}_{V}}$, will be provided in the question.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

