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Question

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A. solid cylinder

B. both together

C. one with higher density

D. hollow cylinder

Answer
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In an inclined plane when a body is getting rolled down, the acceleration is also there which is on the basis of the moment of inertia of the object.

We know that,

As the moment of inertia of a body is higher, then the acceleration of that object will be less. This can be given by the formula,

$a=\dfrac{g\sin \theta }{1+\dfrac{I}{M{{R}^{2}}}}$

Where $a$ the acceleration of a body is, $g$ is the acceleration due to gravity, $\theta $ is the angle of inclination, $I$ is the moment of inertia of the object, $M$ is the mass of the object and $R$ is the radius of the body.

Now for an equal mass and equal radius,

As we know that,

${{I}_{solidcylinder}}<{{I}_{hollowcylinder}}$

Therefore we can write that,

${{a}_{solidcylinder}}>{{a}_{hollowcylinder}}$