# A solid compound XY has $\text{NaCl}$ structure. If the radius of the cation is 100 pm, the radius of the anion $\text{(}{{\text{Y}}^{-}})$ will be:A. 275.1 pmB. 322.5 pmC. 241.5 pmD. 165.7 pm.

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Hint: The division of the radius of cation by the radius of anion gives the radius ratio. It is very helpful in telling the structure of the compound by using the coordination number i.e. more will be the coordination number more is the radius of an ion or atom.

Formula used:

- So, $0.414\text{ = }\frac{\text{Radius of cation (}{{\text{r}}^{-}})}{\text{Radius of anion (}{{\text{r}}^{+}})}$
$0.414\text{ = }\frac{100}{\text{r}}$
$\text{r = }\frac{100}{0.414}\text{ = 241}\text{.5 pm}$