Answer
424.2k+ views
Hint: Law of constant proportions is a law that implies that the sample of a compound will contain the same elements that are present in the same ratio by mass as that of any other sample of the same compound.
Complete answer:
The law of constant proportions states that the chemical compounds are made up of elements that are present in a fixed ratio by mass. This means that a pure sample of a compound, no matter what the source is, will always contain the same elements that are present in the same ratio by mass. Let us now use this law to find the weight of the calcium in 4 g of calcium carbonate.
The percentage compositions of the elements of calcium carbonate are given as: Ca = 40%; C = 12%; O = 48%. As it is also given that the law of constant proportion holds true, then this means that even the sample of 4g of calcium carbonate will have the percentage composition of the constituent elements as: Ca = 40%; C = 12%; O = 48%.
Therefore, this means that 100g of $CaC{O}_{3}$, 40 g of Ca is present.
Thus, in a 4g sample of $CaC{O}_{3}$, let x g of Ca be present.
This means, $\dfrac {x}{4} = \dfrac {40}{100}$
$\implies x = \dfrac {40 \times x}{100}$
$\implies x = 1.6g$
Therefore, the weight of calcium in 4 g of a sample calcium carbonate from another source is 1.6g.
Hence, the correct answer is option (C).
Note: The law of constant proportions does not hold true in all the cases. There are some exceptions too. Some non-stoichiometric compounds have different element composition in different samples. These compounds rather obey the law of multiple proportions.
Complete answer:
The law of constant proportions states that the chemical compounds are made up of elements that are present in a fixed ratio by mass. This means that a pure sample of a compound, no matter what the source is, will always contain the same elements that are present in the same ratio by mass. Let us now use this law to find the weight of the calcium in 4 g of calcium carbonate.
The percentage compositions of the elements of calcium carbonate are given as: Ca = 40%; C = 12%; O = 48%. As it is also given that the law of constant proportion holds true, then this means that even the sample of 4g of calcium carbonate will have the percentage composition of the constituent elements as: Ca = 40%; C = 12%; O = 48%.
Therefore, this means that 100g of $CaC{O}_{3}$, 40 g of Ca is present.
Thus, in a 4g sample of $CaC{O}_{3}$, let x g of Ca be present.
This means, $\dfrac {x}{4} = \dfrac {40}{100}$
$\implies x = \dfrac {40 \times x}{100}$
$\implies x = 1.6g$
Therefore, the weight of calcium in 4 g of a sample calcium carbonate from another source is 1.6g.
Hence, the correct answer is option (C).
Note: The law of constant proportions does not hold true in all the cases. There are some exceptions too. Some non-stoichiometric compounds have different element composition in different samples. These compounds rather obey the law of multiple proportions.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)