
A plane has a take off speed of $88.3 m/s$ and requires 1365 m to reach that speed. Determine the acceleration of the plane.
(A) $3.86m/{s^2}$
(B) $2.86m/{s^2}$
(C) $2.8m/{s^2}$
(D) $2.6m/{s^2}$
Answer
473.4k+ views
Hint:Given problem is straight forward formula based problem. If initial velocity, final velocity and distance or displacement is given and we have to find acceleration then use Newton’s III equation of motion which is
${v^2} = {u^2} + 2as$
Where
u $ = $ Initial velocity
v $ = $ Final velocity
a $ = $ Acceleration
s $ = $ Displacement
Complete step by step answer:
Given that initial velocity of plane is $u = 0 m/s$ final velocity of plane $v = 88.3 m/s$
Distance travelled by plane
$s = 1365 m$
Let a be the acceleration of the plane.
So, using Newton’s III equation of motion
$\Rightarrow {v^2} = {u^2} + 2as$
$\Rightarrow {(88.3)^2} = {(0)^2} + 2a(1365)$
$\Rightarrow 7796.89 = 0 + (2730)a$
$\Rightarrow (2730)a = 7796.89$
$\Rightarrow a = \dfrac{{7796.89}}{{2730}}$
$\Rightarrow a = 2.865$
$\therefore a \simeq 2.86m/{s^2}$
Hence, the acceleration of plane is $2.86m/{s^2}$
So, option B is the correct answer.
Note: In many problems, students may get confused about where and which equation of Newton’s we should apply. So, If acceleration, time and initial velocity is given and we have to find final velocity of the body then we should apply Newton’s I equation.If displacement is asked then we should apply Newton’s II equation.If acceleration is asked and time is not given then we should apply Newton’s III equation.
${v^2} = {u^2} + 2as$
Where
u $ = $ Initial velocity
v $ = $ Final velocity
a $ = $ Acceleration
s $ = $ Displacement
Complete step by step answer:
Given that initial velocity of plane is $u = 0 m/s$ final velocity of plane $v = 88.3 m/s$
Distance travelled by plane
$s = 1365 m$
Let a be the acceleration of the plane.
So, using Newton’s III equation of motion
$\Rightarrow {v^2} = {u^2} + 2as$
$\Rightarrow {(88.3)^2} = {(0)^2} + 2a(1365)$
$\Rightarrow 7796.89 = 0 + (2730)a$
$\Rightarrow (2730)a = 7796.89$
$\Rightarrow a = \dfrac{{7796.89}}{{2730}}$
$\Rightarrow a = 2.865$
$\therefore a \simeq 2.86m/{s^2}$
Hence, the acceleration of plane is $2.86m/{s^2}$
So, option B is the correct answer.
Note: In many problems, students may get confused about where and which equation of Newton’s we should apply. So, If acceleration, time and initial velocity is given and we have to find final velocity of the body then we should apply Newton’s I equation.If displacement is asked then we should apply Newton’s II equation.If acceleration is asked and time is not given then we should apply Newton’s III equation.
Recently Updated Pages
Master Class 11 Accountancy: Engaging Questions & Answers for Success

Glucose when reduced with HI and red Phosphorus gives class 11 chemistry CBSE

The highest possible oxidation states of Uranium and class 11 chemistry CBSE

Find the value of x if the mode of the following data class 11 maths CBSE

Which of the following can be used in the Friedel Crafts class 11 chemistry CBSE

A sphere of mass 40 kg is attracted by a second sphere class 11 physics CBSE

Trending doubts
Define least count of vernier callipers How do you class 11 physics CBSE

The combining capacity of an element is known as i class 11 chemistry CBSE

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Find the image of the point 38 about the line x+3y class 11 maths CBSE

Can anyone list 10 advantages and disadvantages of friction

Distinguish between Mitosis and Meiosis class 11 biology CBSE
