# A picture is painted on cardboard $8cm$long and$5cm$wide such that there is a margin of$1.5cm$along each of its sides. Find the total area of the margin.

Answer

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Hint: Use formula of area of rectangle i.e, $l * b$, where $l$ is length and $b$ is breadth of rectangle.

Given:

Length$\left( l \right)$ and width$\left( b \right)$ of cardboard$ = 8cm$and $5cm$respectively.

And length of margin along each other of its sides$ = 1.5cm$

Therefore area of cardboard including margin$ = l \times b$

$ = 8 \times 5 = 40c{m^2}$

Now excluding margin

Length$ = 8 - 1.5 = 6.5cm$

Width$ = 5 - 1.5 = 3.5cm$

Therefore area of cardboard excluding margin$ = l \times b$

$ = 6.5 \times 3.5 = 22.75c{m^2}$

Therefore area of margin = area of cardboard including margin - area of cardboard excluding margin

$ = 40 - 22.75 = 17.25c{m^2}$

Hence area of margin is $17.25c{m^2}$

Note: - In such types of questions first calculate the total area including margin then area excluding margin then subtract these two areas we will get the required area of margin.

Given:

Length$\left( l \right)$ and width$\left( b \right)$ of cardboard$ = 8cm$and $5cm$respectively.

And length of margin along each other of its sides$ = 1.5cm$

Therefore area of cardboard including margin$ = l \times b$

$ = 8 \times 5 = 40c{m^2}$

Now excluding margin

Length$ = 8 - 1.5 = 6.5cm$

Width$ = 5 - 1.5 = 3.5cm$

Therefore area of cardboard excluding margin$ = l \times b$

$ = 6.5 \times 3.5 = 22.75c{m^2}$

Therefore area of margin = area of cardboard including margin - area of cardboard excluding margin

$ = 40 - 22.75 = 17.25c{m^2}$

Hence area of margin is $17.25c{m^2}$

Note: - In such types of questions first calculate the total area including margin then area excluding margin then subtract these two areas we will get the required area of margin.

Last updated date: 29th Sep 2023

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