Question

A pea plant with blue color flower by BB is crossbred with a pea plant with white flower denoted by ww.
a. What is the expected color of the flowers in their F1, progeny?
b. What will be the percentage of plants bearing white flowers in F2, generation, when the flowers of F1, plants were selfed?
c. State the expected ratio of the genotype BB and Bw in the F2, progeny?

Answer 1

Hint:-George Mendel was the German scientist who was done lot of research in the field of genetics, he is considered as founder of modern genetics, where he is one who done experiment to explain inheritance, and proposed law of inheritance, law of segregation and law of independent assortment.

Complete step-by-step solution:-Mandela in order to know the genotype and phenotype of the individuals, he did experiments, which called as true crossing or true breeding.
If the crossing done by using one trait is said to be monohybrid cross.
The result of Monohybrid cross from Parents gives the F1 generation, and the self fertilization of F1 generation gives the F2 generation.
A) So in the question they give the parents plants such as blue BB, and the ww white. Where Blue is dominant and w is recessive.
So the parents are BB( blue ) and ww (white).
BB. × ww gives the 4 Bw.which is F1 generation.
So the genotype of all offspring in F1 generation is Bw, and the phenotypic expression is blue.
B) The self fertilization of F1 gives the F2, they are

	B	w
B	BB	Bw
w	Bw	ww

Note:- Genotype is the genetic makeup of an individual for a particular trait, where the phenotype means expression of genotype, where the genotype of flowers are BB, Bw and the phenotype of those genotypes gives blue color to the flowers.