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A $N{a_2}C{O_3} + xHCl \to 2NaCl + C{O_2} + {H_2}O$
The value of $x$ is:
A. 1
B. 2
C. 3
D. 4

Last updated date: 16th Jul 2024
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Hint: In order of the question, first we have to compare the number of atoms of each element separately. Then, balance the correct initial reaction. Then only, we will get the value of $x$.

Complete step-by-step answer:
For balancing any chemical reaction, the elements that are present in reactant should also be present in the product.
Now, we should write the correct initial reaction without coefficients:-
$N{a_2}C{O_3} + HCl \to NaCl + C{O_2} + {H_2}O$
In the above reaction,
The total number of atoms in $Na$ is 2 in the reactant side, while the number of atoms is 1 in the product side. So, for balancing $Na$ element, we should add 2 coefficients in product side $Na$ element.
Similarly, we should add 2 coefficients in the $HCl$ compound also.
Now, we compare the number of atoms per element, this process starts with every single element. After balancing, the corrected reaction would be:
$N{a_2}C{O_3} + 2HCl \to 2NaCl + C{O_2} + {H_2}O$
Now, the above reaction is accurately balanced. So, the coefficient of $HCl$, instead of $x$ is 2.

Therefore, the value of $x$ is 2. Hence the correct option is (B). 2.

Note: Balance any reaction helps to obtain or prepare a perfect chemically balanced compound for better implementations. Balancing chemical reaction is important as it is only rearrangement of the atoms.