Answer
Verified
417.9k+ views
Hint: Since the man is pulling the block on which he is standing hence the blocks mass will not come under consideration. We need to use the expression for Newton’s second law of motion. Draw a free body diagram of the man. We need to apply Newton’s second law of motion to the man in a vertical direction and derive the equation for the normal force exerted by the surface of the board on the man.
Formula Used: The formulae used in the solution are given here.
$ {F_{net}} = ma $ where $ {F_{net}} $ is the net force acting on the object, $ m $ is the mass of the object and $ a $ is acceleration of the object.
Complete Step by Step Solution
We have given that a man of mass $ m $ is standing on the board and pulling the same board of mass $ M $ with a force $ F $ .
Let us first draw the free body diagram of the man.
In the above free body diagram, $ mg $ is the weight of the man acting in the downward direction, $ F $ is the force by which the man is pulling up the board and $ N $ is the normal force exerted by the surface of the board on the man.
The man is in a steady state with no motion in any direction. Hence, the acceleration of the man is zero. Hence, the right hand side term in the expression of Newton’s second law of motion becomes zero.
Apply Newton’s second law of motion on the man in the vertical direction.
$ F + N - mg = 0 $
$ \Rightarrow N = mg - F $
Therefore, the normal force exerted by the surface of the board on man is $ mg - F $ .
So, the correct answer is “Option A”.
Note
The students may apply Newton’s second law of motion to the whole system of man, board and pulley. But the answer for the normal force obtained in such a way is not in the given options and it will be incorrect also as we have asked only the normal force exerted by the board surface on the man.
Formula Used: The formulae used in the solution are given here.
$ {F_{net}} = ma $ where $ {F_{net}} $ is the net force acting on the object, $ m $ is the mass of the object and $ a $ is acceleration of the object.
Complete Step by Step Solution
We have given that a man of mass $ m $ is standing on the board and pulling the same board of mass $ M $ with a force $ F $ .
Let us first draw the free body diagram of the man.
In the above free body diagram, $ mg $ is the weight of the man acting in the downward direction, $ F $ is the force by which the man is pulling up the board and $ N $ is the normal force exerted by the surface of the board on the man.
The man is in a steady state with no motion in any direction. Hence, the acceleration of the man is zero. Hence, the right hand side term in the expression of Newton’s second law of motion becomes zero.
Apply Newton’s second law of motion on the man in the vertical direction.
$ F + N - mg = 0 $
$ \Rightarrow N = mg - F $
Therefore, the normal force exerted by the surface of the board on man is $ mg - F $ .
So, the correct answer is “Option A”.
Note
The students may apply Newton’s second law of motion to the whole system of man, board and pulley. But the answer for the normal force obtained in such a way is not in the given options and it will be incorrect also as we have asked only the normal force exerted by the board surface on the man.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Mark and label the given geoinformation on the outline class 11 social science CBSE
When people say No pun intended what does that mea class 8 english CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Give an account of the Northern Plains of India class 9 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Trending doubts
Difference Between Plant Cell and Animal Cell
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Which are the Top 10 Largest Countries of the World?
One cusec is equal to how many liters class 8 maths CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
The mountain range which stretches from Gujarat in class 10 social science CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths