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# A long rubber tube having mass $0.9kg$ is fastened to a fixed support and the free end of the tube is attached to a chord which passes over a pulley and supports an object, with a mass of $5kg$ as shown in figure. If the tube is struck by a transverse blow at one end, the time required for the pulse to reach the other end is (neglect the variation of speed due to the mass of the tube)(A) $5s$ (B) $0.48s$ (C) $4.8s$ (D) $3.2s$

Last updated date: 13th Jun 2024
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Hint To solve this question, we have to determine the speed of the sound in the rubber tube from the formula given as $v = \sqrt {\dfrac{T}{\mu }}$ . Then using the general formula of the speed in terms of the distance covered, we can find out the value of the time required for the pulse to reach the other end.

Formula Used The formula used in solving this question is given by
$\Rightarrow v = \sqrt {\dfrac{T}{\mu }}$, here $v$ is the speed of the wave in a string having the mass density of $\mu$, which is stretched by a tension of $T$ .

Let us consider the tension in the cord as $T$
So the free body diagram for the mass $5kg$ will be as,

From the condition of vertical equilibrium we get,
$\Rightarrow T = mg$
According to the question $m = 5kg$ . So we have
$\Rightarrow T = 5g$ ….(1)
Now, the velocity of sound in a stretched string is given by the formula,
$\Rightarrow v = \sqrt {\dfrac{T}{\mu }}$ …...(2)
We know that $\mu$ is the mass per unit length. So the mass per unit length for the rubber tube, which is of length $12m$ is and mass $0.9kg$ is
$\therefore \mu = \dfrac{M}{l}$
$\Rightarrow \mu = \dfrac{{0.9}}{{12}} = 0.075kg/m$ …….(3)
Putting (1) and (3) in (2) we get
$\Rightarrow v = \sqrt {\dfrac{{5g}}{{0.075}}}$
Putting $g = 9.8m/{s^2}$ we get,
$\Rightarrow v = \sqrt {\dfrac{{49}}{{0.075}}}$
On solving we get the value of the velocity as,
$\Rightarrow v = 25.56m/s$ …...(4)
Now, the rubber tube is struck by the transverse blow at one end. The total distance covered to reach the other end will be equal to the length of the tube. So we have
$\Rightarrow d = 12m$ …..(5)
So, the time required for the wave to reach the other end is given by the formula
$\Rightarrow t = \dfrac{d}{v}$
Putting (4) and (5) in the above formula we get,
$\Rightarrow t = \dfrac{{12}}{{25.56}}$
On solving we get,
$\Rightarrow t = 0.47s$
From the options the nearest matching value is $0.48s$ . So we take
$\Rightarrow t \approx 0.48s$
Hence the correct answer is option (B).

Note
We should not calculate the tension in the rubber tube separately. This is because the tube is not freely hanging but it is fastened to the fixed support below it. So, its weight does not increase the tension in it. Hence, the tension in the tube will be equal to the tension due to the weight of the hanging block.