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$

(a){\text{ }}1800 \\

(a){\text{ }}200 \\

(a){\text{ }}2000 \\

(a){\text{ }}2150 \\

$

Answer
Verified

Hint: The garden of given dimensions forms a rectangle of length 24m and breadth 14m. The 1 meter wide path to the exterior of the garden will eventually increase its length and breadth by 2m, 1m at top and 1 m at bottom in case of breadth, 1m more at left and 1 m more at right in case of length. It will be clearer after the pictorial representation of the dimensions.

Now the given dimension of garden is $24m \times 14m$.That is length = 24m and breadth = 14m

As we know that the area of rectangle is given as ${\text{length }} \times {\text{ breadth}}$â€¦â€¦â€¦â€¦â€¦â€¦â€¦ (1)

Substituting the values in equation (1) we get

Area of garden = $24 \times 14 = 336{\text{ }}{{\text{m}}^2}$â€¦â€¦â€¦â€¦â€¦â€¦â€¦â€¦â€¦â€¦. (2)

Now as discussed above and by the diagram it is clear that this 1m wide path to the exterior of the garden contributes in addition up to 2m in length and 2m in breadth of original garden.

So dimensions of the garden including path is $\left( {24 + 2,14 + 2} \right) = 26{\text{m}} \times 16m$.That is length is 26m and breath is 14m.

Substituting the values in equation (1) we get

Area of garden including the path = $26 \times 16 = 416{{\text{m}}^2}$â€¦â€¦â€¦â€¦â€¦â€¦â€¦â€¦. (3)

Now clearly Area of path = Area of garden with path â€“ Area of garden

So using equation (2) and equation (3) we get

Area of path = $416 - 336 = 80{\text{ }}{{\text{m}}^2}$= $80 \times {10^4}{\text{ c}}{{\text{m}}^2}$ as (1m=100 cm so 1${m^2} = 10000c{m^2}$)â€¦â€¦â€¦â€¦â€¦â€¦. (4)

Now this path is to be constructed with tiles of dimensions $20{\text{cm}} \times {\text{20cm}}$. Side = 20 cm

Now by observation of the dimensions of tile it is clear that tile is a square, thus area of square is ${\left( {side} \right)^2}$â€¦â€¦â€¦â€¦â€¦â€¦â€¦.. (5)

Substituting the value in equation (5) we get

Area of tile = ${\left( {20} \right)^2} = 400{\text{ c}}{{\text{m}}^2}$â€¦â€¦â€¦â€¦â€¦â€¦â€¦â€¦â€¦â€¦.. (6)

Now the total number of tiles required for pavement of the entire 1m wide path will be $\dfrac{{{\text{Area of path}}}}{{{\text{Area of tile}}}}$â€¦â€¦â€¦â€¦â€¦â€¦â€¦â€¦â€¦â€¦ (7)

Putting values in equation (7) from equation (4) and equation (6) we get

Number of tiles = $\dfrac{{8,00,000}}{{400}} = 2000$

So in total 2000 tiles are required for pavement of the entire 1m wide path around the garden.

Note: Whenever we face such type of problems the key points that we need to remember is that firstly try and figure out the area of the path that lies exterior or interior to the garden, then find the area of the tiles that need to cover this path, simple division of area of path to that of area of tile will get you to the answer.

Now the given dimension of garden is $24m \times 14m$.That is length = 24m and breadth = 14m

As we know that the area of rectangle is given as ${\text{length }} \times {\text{ breadth}}$â€¦â€¦â€¦â€¦â€¦â€¦â€¦ (1)

Substituting the values in equation (1) we get

Area of garden = $24 \times 14 = 336{\text{ }}{{\text{m}}^2}$â€¦â€¦â€¦â€¦â€¦â€¦â€¦â€¦â€¦â€¦. (2)

Now as discussed above and by the diagram it is clear that this 1m wide path to the exterior of the garden contributes in addition up to 2m in length and 2m in breadth of original garden.

So dimensions of the garden including path is $\left( {24 + 2,14 + 2} \right) = 26{\text{m}} \times 16m$.That is length is 26m and breath is 14m.

Substituting the values in equation (1) we get

Area of garden including the path = $26 \times 16 = 416{{\text{m}}^2}$â€¦â€¦â€¦â€¦â€¦â€¦â€¦â€¦. (3)

Now clearly Area of path = Area of garden with path â€“ Area of garden

So using equation (2) and equation (3) we get

Area of path = $416 - 336 = 80{\text{ }}{{\text{m}}^2}$= $80 \times {10^4}{\text{ c}}{{\text{m}}^2}$ as (1m=100 cm so 1${m^2} = 10000c{m^2}$)â€¦â€¦â€¦â€¦â€¦â€¦. (4)

Now this path is to be constructed with tiles of dimensions $20{\text{cm}} \times {\text{20cm}}$. Side = 20 cm

Now by observation of the dimensions of tile it is clear that tile is a square, thus area of square is ${\left( {side} \right)^2}$â€¦â€¦â€¦â€¦â€¦â€¦â€¦.. (5)

Substituting the value in equation (5) we get

Area of tile = ${\left( {20} \right)^2} = 400{\text{ c}}{{\text{m}}^2}$â€¦â€¦â€¦â€¦â€¦â€¦â€¦â€¦â€¦â€¦.. (6)

Now the total number of tiles required for pavement of the entire 1m wide path will be $\dfrac{{{\text{Area of path}}}}{{{\text{Area of tile}}}}$â€¦â€¦â€¦â€¦â€¦â€¦â€¦â€¦â€¦â€¦ (7)

Putting values in equation (7) from equation (4) and equation (6) we get

Number of tiles = $\dfrac{{8,00,000}}{{400}} = 2000$

So in total 2000 tiles are required for pavement of the entire 1m wide path around the garden.

Note: Whenever we face such type of problems the key points that we need to remember is that firstly try and figure out the area of the path that lies exterior or interior to the garden, then find the area of the tiles that need to cover this path, simple division of area of path to that of area of tile will get you to the answer.

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