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# A fraction becomes equal to $\dfrac{4}{5}$ if $1$ is added to both the numerator and the denominator. If, however, $5$ is subtracted from both the numerator and denominator, the fraction becomes equal to $\dfrac{1}{2}$. What is the fraction?  Answer Verified
Hint: Approach the solution by considering a fraction and proceed with further simplification by applying the given conditions.

Let us consider the fraction as $\dfrac{x}{y}$
By applying the ${1^{st}}$ condition we will get
$\Rightarrow \dfrac{{x + 1}}{{y + 1}} = \dfrac{4}{5}$
On further simplification we will get
$\ \Rightarrow 5\left( {x + 1} \right) = 4\left( {y + 1} \right) \\ \Rightarrow 5x + 5 = 4y + 4 \\ \$
$\Rightarrow 5x - 4y = - 1$$\to (1)$
And now by applying ${2^{nd}}$condition we will get
$\ \Rightarrow \dfrac{{x - 5}}{{y - 5}} = \dfrac{1}{2} \\ \\ \$
On further simplification we will get
$\ \Rightarrow 2(x - 5) = 1(y - 5) \\ \Rightarrow 2x - 10 = y - 5 \\ \Rightarrow 2x - y = - 5 + 10 \\ \$
$2x - y = 5 \to (2)$
For further calculation multiply equation $(2) \times 4$
$\ \Rightarrow 4 \times (2x - y = 5) \\ \Rightarrow 8x - 4y = 20 \to (3) \\ \$
Now subtract equation $(3)$ from equation $(1)$ we get
$x = 7$
Putting $x = 7$ in equation $(2)$ we get
$\ \Rightarrow 2x - y = 5 \\ \Rightarrow 2(7) - y = 5 \\ \Rightarrow y = 9 \\ \$
Here we got both $x\& y$ values
Therefore required fraction is $\dfrac{x}{y} = \dfrac{7}{9}$
Note: Apply the conditions in a step-by-step process with the proper approach to get the answer as the given problem is full of simplification.
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